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3 years ago

I need help on 2,5,9

Mathematics

1 answer:

USPshnik [31]3 years ago

3 0

Answer:

2. -4/3

5. 128/105

9. -5/6

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The perimeter of a square is 12x - 8. Which of the following is the length of

Andrei [34K]

Answer:

3x-2

Step-by-step explanation:

12x-8/4 = 3x-2 is one side length of a square

3 0

3 years ago

A rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet. Describe the possible lengths o

kipiarov [429]

Answer: 51.86 and 23.14

Step-by-step explanation:

The rectangular garden must have a perimeter of 150 feet

Perimeter of rectangular garden =

2l + 2w=150 -----------1

The rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet.

Area of rectangular garden =

l×w= 1200 feet^2 -----------2

From equation 2, l=1200/w

Put l=1200/w in equation 1

2× 1200/w + 2w = 150

(2400/w) +2w = 150

(2400+2w^2)/w =150

2400+2w^2= 150w

2w^2- 150w+2400=0

Using the general formula

w = [-b+-√(b^2-4ac)]/2a

a = 2, b =-150, c=2400

w =[--150+/-√(-150^2-4×2×2400)]/2×2

=[150+/-√(22500-19200)]/4

=[150+/-√3300)]/4

=(150+57.45)/4 or (150-57.45)/4

w= 207.45/4 or 92.55/4

w= 51.86 or w= 23.14

l = 1200/51.86 or l= 1200/23.14

l = 23.14. or l= 51.86

For an area of at least 1200ft^2

The dimensions are 51.86 and 23.14

4 0

3 years ago

WHY ISNT ANYBODY ANSWERING MY QUESTION PS HELP MEEEEE I ALWAYS GIVE BRAINLIEST 5 STARS andddd offer 25 pointsssssssssss plsss he

meriva

Answer:

0.5 I think. because for every 2 on the x axis, it grows 1 on the y axis.

6 0

3 years ago

From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.

zzz [600]

Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

$\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}$

, where $\overline{x}$ = sample mean.

z*= critical z-value

n= sample size.

$\sigma$ = Population standard deviation.

By considering the given question , we have

$\overline{x}= 21.69$

$\sigma=3.23$

n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

$21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}$

$=21.69\pm (1.96)\dfrac{1.7}{7.61577}$

$=21.69\pm (1.96)(0.223221)$

$\approx21.69\pm0.83$

$=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)$

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

7 0

3 years ago

At a doctor's appointment, a baby weighed 10 pounds. How many ounces did the baby weigh?

Sergio [31]

Answer:

The baby would be 160 ounces.

Step-by-step explanation:

4 0

3 years ago