To find the expression for the area of the rectangular garden we will find the area of the rectangle in the picture and then double it.
Area of the garden will be represented by the expression 32s⁵ ft².
Mrs. Lopez is designing her rectangular garden which is 2 times greater than the area of the rectangle shown in the picture.
Dimensions of the rectangle in the picture are 4s³t ft and 8s² ft.
Therefore, area of the rectangle in the picture = Length × Width
= 4s³t × 8s²
= 32s⁵t ft²
Since, area of the garden is 2 times greater than the area of the rectangle given in the picture.
Therefore, area of the garden = 2(area of the rectangle given in the garden)
= 2(32s⁵t) square feet.
= 64s⁵t square feet
Learn more,
brainly.com/question/17419256
x = 1
5(1)= -4y + 4
5= -4y + 4
-4. -4 1 = -4y
y = -¼
x = 2...
10 = -4y + 4 6 = -4y y = -3/2
x = 3..
15 = -4y + 4 11 = -4y y = -11/4
Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
