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3 years ago

Ms. Taylor's checking account changes by-$1146 every year on her

Mathematics

1 answer:

ddd [48]3 years ago

3 0

Answer:

-95.5

Step-by-step explanation:

if you do -1146 divided by 12 you get -95.5

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A survey was conducted that asked 1004 people how many books they had read in the past year. Results indicated that x overbarequ

melisa1 [442]

Answer:

Step-by-step explanation:

Given that a survey was conducted that asked 1004 people how many books they had read in the past year.

Results are:

x bar =12.5

s = 16.6

n = 1004

Std error of sample = $\frac{s}{\sqrt{n-1} } =\frac{16.6}{\sqrt{1003} }\\=0.524152\\=0.524$

Since population std dev is not known t critical value can be used for confidence interval.

df = 1004-1 =1003

t critical = 1.96

Margin of error $= 1.96(std error) =1.027$

Confidence interval lower bound $= 12.5-1.027 = 11.473$

Upper bound $= 12.5+1.027 = 13.527$

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3 years ago

What is the y in 10.3=0.6y

ollegr [7]

Hello, you would divide 10.3 by 0.6 to get 17.166 repeating. So y equals 17.166.

6 0

3 years ago

What 7/16 + 9/16 equal to.

Diano4ka-milaya [45]

Hi,

Equation;

$\frac{7}{16} + \frac{9}{16} = \frac{16}{16} = 1$

Hope this helps.
r3t40

8 0

3 years ago

Read 2 more answers

A military aircraft can travel 740 miles per hour. The distance between Tyndall Air Force Base in Florida and Lakenheath Air For

BARSIC [14]

Answer: 3.5 h

Step-by-step explanation:

1. Data:

a) s = 740 miles / h

b) d = 2,567 miles

c) t = ?

2. Equation:

speed = distance / time

s = d / t

3. Solution:

Solve the equation for t:

s = d / t ⇒ t = d / s

Substitute values:

t = 2,567 miles / (740 miles/h) ≈ 3.47 h ≈ 3.5 h

5 0

3 years ago

Find the length of the tangent segment AB to the circles centered at O and O' whose radii are a and b respectively when the circ

bixtya [17]

Answer:

$AB=2\sqrt{ab}$

Step-by-step explanation:

From figure,

$OA=a, \quad \quad O'B=b\\\Rightarrow OO'= (a+b) \quad \quad \text{and}\quad OD=(a-b)$

In triangle $OO'D$

$(OO')^2=(OD)^2+(O' D)^2$

$\Rightarrow (a+b)^2=(a-b)^2+(O' D)^2\\\Rightarrow a^2+b^2+2ab-a^2-b^2+2ab=(O' D)^2\\\Rightarrow 4ab=(O' D)^2\\\Rightarrow O'D=2\sqrt{ab} \\\Rightarrow O' D=2\sqrt{ab}=AB \quad \quad [\because O' DAB\;\; \text{is a rectangle.}]$

Hence, $AB=2\sqrt{ab}$

6 0

3 years ago