Question

What is the equation of a circle with Center -3, -5 and radius 4

Answer 1

The formula is (x-h)^2+(y-k)^2=r^2
so, using this, and knowing that h is -3 and k is -5 and r is 4, we get

(x--3)^2+(y--5)^2=(4)^2, which equals
(X+3)^2+(y+5)^2=16

:)

Answer 2

Answer:

$(x+3)^2+(y+5)^2= 16$

Step-by-step explanation:

the equation of a circle with Center -3, -5 and radius 4

center is (-3, -5) and radius = 4

Equation of a circle is

$(x-h)^2+(y-k)^2= r^2$

Where (h,k) is the center and r is the radius of the circle

Given center is (-3, -5) . h= -3 and k= -5

WE plug in the value of h , k and r

$(x-h)^2+(y-k)^2= r^2$

$(x-(-3))^2+(y-(-5))^2= 4^2$

$(x+3)^2+(y+5)^2= 16$