Okay, to find this you have to subtract smallest from biggest, in this case it would be 98-78, so therefore the range would be 20.
Hope that helped!
So what is your question here?
<span>(3x^3-4x^2-5x+3)+(-4 - 6x^3+x^2 - 5x+5)
= </span><span>3x^3 - 4x^2 - 5x + 3 - 4 - 6x^3 + x^2 - 5x + 5
= -3x^3 - 3x^2 - 10x + 4</span>
Answer:
<em><u>Equivalent</u></em><em><u> </u></em><em><u>fractions</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>5</u></em><em><u>/</u></em><em><u>3</u></em><em><u> </u></em><em><u>are-</u></em>
- <em><u>5</u></em><em><u>/</u></em><em><u>3</u></em><em><u>×</u></em><em><u>2</u></em><em><u>/</u></em><em><u>2</u></em><em><u>=</u></em><em><u>1</u></em><em><u>0</u></em><em><u>/</u></em><em><u>6</u></em>
- <em><u>5</u></em><em><u>/</u></em><em><u>3</u></em><em><u>×</u></em><em><u>3</u></em><em><u>/</u></em><em><u>3</u></em><em><u>=</u></em><em><u>1</u></em><em><u>5</u></em><em><u>/</u></em><em><u>9</u></em>
- <em><u>5</u></em><em><u>/</u></em><em><u>3</u></em><em><u>×</u></em><em><u>4</u></em><em><u>/</u></em><em><u>4</u></em><em><u>=</u></em><em><u>2</u></em><em><u>0</u></em><em><u>/</u></em><em><u>1</u></em><em><u>2</u></em>
<h3>
Answer: </h3><h3>Fred has <u>20 students</u> and Lee has <u>22 students</u></h3>
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Work Shown:
L = number of students in Lee's class
F = number of students in Fred's class
Lee has 1.1 times as many students compared to Fred
This means we have this equation
L = 1.1F
Whatever the value of F is, we multiply that by 1.1 to get the value of L
The two amounts L and F add to 42 total students
L+F = 42
1.1F + F = 42 .... replace L with 1.1F
2.1F = 42
F = 42/(2.1)
F = 20 .... Fred has 20 students
L = 1.1*F
L = 1.1*20
L = 22 .... Lee has 22 students
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Check:
L+F = 22+20 = 42
this confirms the answer