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hodyreva [135]
3 years ago
10

Help me with this math problem please

Mathematics
2 answers:
AnnyKZ [126]3 years ago
7 0
The answer is 4 to the power of 0
lianna [129]3 years ago
3 0
The expression
{4}^{5}  \times  {4}^{ - 7}  \div  {4}^{ - 2}
is the same as
\frac{ {4}^{5}  \times  {4}^{ - 7} }{ {4}^{ - 2} }
Which, if we switch the negative exponents, equals
\frac{ {4}^{5} \times  {4}^{2}  }{ {4}^{7} }
And if we combine them, they equal
\frac{ {4}^{7} }{ {4}^{7} }
Then we divide, and they equal
{4}^{0}
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3 years ago
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sveticcg [70]

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3 0
2 years ago
Find f (2b^2) for (x)=x^2-4x
BlackZzzverrR [31]

Answer:

A

Step-by-step explanation:

We are given the function:

f(x) = x^2 - 4x

And we want to find:

\displaystyle f(2b^2)

Substitute:

\displaystyle f(2b^2) =(2b^2)^2 -4(2b^2)

And evaluate:

\displaystyle \begin{aligned}  f(2b^2) &=(2b^2)^2 -4(2b^2) \\ &=(4b^4) +(-8b^2) \\ &= 4b^4 - 8b^2 \end{aligned}

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7 0
3 years ago
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8 0
3 years ago
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5 0
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