From the standard normal tables, obtain
P(z<1.95) = 0.9744
P(z<0.37) = 0.6443
P(z<1.32) = 0.9066
P(z<1.82) = 0.9656
P(z<1.05) = 0.8531
P(z<2.05) = 0.9798
P(z<0.03) = 0.5120
P(z<0.53) = 0.7019
Answers:
Range of z Area
-------------- ---------------------------------------
a. 0 - 1.95 0.9744
b. 0 - 0.37 0.6443
c. 1.32 - 1.82 0.9656 - 0.9066 = 0.0590
d. 1.05 - 2.05 0.9798 - 0.8531 = 0.1267
e. 0.03 - 0.53 0.7019 - 0.5120 = 0.1899
Answer:
A, B, and C
Step-by-step explanation:
The discriminant is denoted by b^2 - 4ac, and it can give us information about the roots of the quadratic equation.
It tells us that if:
- b^2 - 4ac < 0 , then there are 0 real solutions; they're all imaginary (involving the letter i, which is the square root of -1)
- b^2 - 4ac = 0 , then there is 1 real solution; this 1 solution has a multiplicity of 2 because the roots of the quadratic are the same number
- b^2 - 4ac > 0 , then there are 2 real solutions; there are no imaginary solutions
Looking at the possible choices, we see that all of A (A, I'm assuming you meant to write "if the discriminant is zero there is one real solution"), B, and C reflect the above properties.
Thus, they're all right.
Answer:
y = 1/2x-3
Step-by-step explanation:
y=mx+b, where m is slope and b is y-int and x and y are variables.
y = 1/2x-3
Plot your point at (8,1) and then use your slope and rise 1 go over 2 then draw your line.
Hope that helps
