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mina [271]
3 years ago
8

Find the maximum and minimum value of: 1/X plus 3xroot X plus root (4-x)​

Mathematics
1 answer:
Eddi Din [679]3 years ago
7 0
Evet hocam proje konularını da bir bir insan değilim ki bir uyu bir insan bir arar bir insan bir şey var
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Which is greater 1/5 or 2/8
mojhsa [17]
1/5 = 0.2
2/8 = 0.25

1/5 is less than 2/8
2/8 is greater than<span> 1/5</span>

<span>1/5 </span><<span> 2/8</span>
<span>2/8 </span>><span> 1/5</span>
7 0
3 years ago
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(2+x)dy/dx=3y need help
den301095 [7]
(2+x) \frac{dy}{dx} =3y
\frac{1}{3y} dy= \frac{1}{2+x} dx
\int { \frac{1}{3y} } \, dy = \int { \frac{1}{2+x} } \, dx
\frac{1}{3}\ln(3y) = \ln(2+x) + C
(raise both to the power e): e^{ \frac{1}{3}\ln(3y)}=e^{\ln(k(2+x))}
(3y)^ \frac{1}{3} =k(2+x)
3y=k(2+x)^3
y= k(2+x)^3
5 0
3 years ago
A candidate for mayor plans to campaign at 5 shopping malls before the election
miskamm [114]

Answer:

120 ways

Step-by-step explanation:

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6 0
4 years ago
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people with severe hearing loss given a sentence and word recognition test six months after they got implants in their ears the
kirza4 [7]
That would be .82 as 82% is 82/100 so that makes the answer .82
8 0
3 years ago
A multiple-choice test has 30 questions and each one has five possible answers, of which only one is correct. If all answers wer
kumpel [21]

Answer: the probability is 0.13

Step-by-step explanation:

First, each question has 5 options and only one is correct.

Then, selecting at random, the probability of getting a correct answer is equal to:

p = 1/5 = 0.20 (and the probability of getting it incorrect is p = 4/5 = 0.80)

Now, if out of 30 questions, we got 4 correct and 26 incorrect, the probability for a given combination is;

p = (0.20^4)*(0.80^26)

But we also need to multiply this by the total number of combinations.

This is we have 30 questions in total, and we can select 4 of them that will be the correct ones.

Now, if we have N objects in total, the number of different combinations of K elements out of those N elements is

C = \frac{N!}{(N-K)!*K!}

In this case, N = 30 and K = 4.

C = \frac{30!}{(30 -4)!*4!} = \frac{30*29*28*27}{4*3*2}  = 27,405

Then the probability of getting exactly 4 correct answers is:

P = (0.20^4)*(0.80^26)*27,405 = 0.13

5 0
3 years ago
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