1. 10x
2. 18g
3. 6m
4. 4p
5. -5y
6. 9w
7. c^2+3d
8. 3a^2+2b^2+6a
9. 3x^2+x
10. 16x-y+3
11. 68x^2-34x-1
12. 32
13. 32
14. -9
15. 3m+3n
16. 6x-6y
17. 15f+5
If you're talking about Egyptian, you have to put 9 "ten" symbols on the paper and you get 90.
The "ten" symbol looks like a tiny arch.
Answer:
(a)0.5
(b)0.17
(c)0.625
(b)0.375
Step-by-step explanation:
Pr(E)=0.6
Pr(F)=0.2
![Pr(E\cap F)=0.1.](https://tex.z-dn.net/?f=Pr%28E%5Ccap%20F%29%3D0.1.)
(a)Pr (E|F )
![Pr (E|F )=\dfrac{Pr(E \cap F)}{Pr(F)} \\=\dfrac{0.1}{0.2}\\\\=0.5](https://tex.z-dn.net/?f=Pr%20%28E%7CF%20%29%3D%5Cdfrac%7BPr%28E%20%5Ccap%20F%29%7D%7BPr%28F%29%7D%20%5C%5C%3D%5Cdfrac%7B0.1%7D%7B0.2%7D%5C%5C%5C%5C%3D0.5)
(b)Pr (F|E )
![Pr (F|E )=\dfrac{Pr(E \cap F)}{Pr(E)} \\=\dfrac{0.1}{0.6}\\\\=0.17](https://tex.z-dn.net/?f=Pr%20%28F%7CE%20%29%3D%5Cdfrac%7BPr%28E%20%5Ccap%20F%29%7D%7BPr%28E%29%7D%20%5C%5C%3D%5Cdfrac%7B0.1%7D%7B0.6%7D%5C%5C%5C%5C%3D0.17)
(c)Pr (E|F')
Pr(F')=1-P(F)
=1-0.2=0.8
![Pr(E \cap F')=P(E)-P(E\cap F)\\=0.6-0.1\\=0.5](https://tex.z-dn.net/?f=Pr%28E%20%5Ccap%20F%27%29%3DP%28E%29-P%28E%5Ccap%20F%29%5C%5C%3D0.6-0.1%5C%5C%3D0.5)
Therefore:
![Pr (E|F' )=\dfrac{Pr(E \cap F')}{Pr(F')} \\=\dfrac{0.5}{0.8}\\\\=0.625](https://tex.z-dn.net/?f=Pr%20%28E%7CF%27%20%29%3D%5Cdfrac%7BPr%28E%20%5Ccap%20F%27%29%7D%7BPr%28F%27%29%7D%20%5C%5C%3D%5Cdfrac%7B0.5%7D%7B0.8%7D%5C%5C%5C%5C%3D0.625)
(d)Pr(E'|F')
![P(E'\cap F')=P(E \cup F)'\\=1-P(E \cup F)\\=1-[P(E)+P(F)-P(E\cap F)]\\=1-[0.6+0.2-0.1]\\=1-0.7\\=0.3](https://tex.z-dn.net/?f=P%28E%27%5Ccap%20F%27%29%3DP%28E%20%5Ccup%20F%29%27%5C%5C%3D1-P%28E%20%5Ccup%20F%29%5C%5C%3D1-%5BP%28E%29%2BP%28F%29-P%28E%5Ccap%20F%29%5D%5C%5C%3D1-%5B0.6%2B0.2-0.1%5D%5C%5C%3D1-0.7%5C%5C%3D0.3)
Therefore:
![Pr (E'|F' )=\dfrac{Pr(E' \cap F')}{Pr(F')} \\=\dfrac{0.3}{0.8}\\\\=0.375](https://tex.z-dn.net/?f=Pr%20%28E%27%7CF%27%20%29%3D%5Cdfrac%7BPr%28E%27%20%5Ccap%20F%27%29%7D%7BPr%28F%27%29%7D%20%5C%5C%3D%5Cdfrac%7B0.3%7D%7B0.8%7D%5C%5C%5C%5C%3D0.375)
Answer:
(x-10)^2 + (y-2)^2 = 49
Step-by-step explanation:
I'm assuming that 10-2 means (10,2)
Equation of circle:
(x-a)^2 + (y-b)^2 = r^2
Plugging in the values that we know:
(x-10)^2 + (y-2)^2 = 7^2
(x-10)^2 + (y-2)^2 = 49
Hope this helps!