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Katena32 [7]
3 years ago
11

Is the answer B or C

Mathematics
1 answer:
klio [65]3 years ago
6 0

We will calculate it like this, We will make a right angle triangle by adding one new point called O for example, and O is located right under the point C, and on the right side of point D, so the coordinated for this point are O (8, -2). From there, length CD is calculated using the Pythagorean theorem, because we know that the CO = 4 and DO = 4, so:

CD^2 = CO^2 + DO^2

CD^2 = 4^2 + 4^2

DC^2 = 16 + 16

DC^2 = 32

DC = square root of 32 = square root of 16 * square root of 2

DC = 4 * square root of 2

The correct answer is B. 4*square root of 2.

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Range of f(x) = x2 + 1?
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Given the functions below, find g(5) + h(2).<br> g(x) = 2x - 5<br> h(x) = 4x + 5
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G(5) = 2(5)-5=5
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3 years ago
A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard
bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44

In point a)  

\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}

  = \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2

value= (1- \frac{1}{k^2}) \times 100 \% =75\%

In point b)

\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma  \\\\= |(x-\mu)|\leq 2.5 \times 4.44  \\\\  = |(x-\mu)|\leq 1.11 \\\\ =  (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)

In point c)

\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\

In point d)

using standard normal variate

x=20.17\\\\  z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17

8 0
3 years ago
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