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puteri [66]
3 years ago
9

I need help with Math ASAP plz !!

Mathematics
1 answer:
Elina [12.6K]3 years ago
6 0

Answer: 1 square and 4 triangles

Step-by-step explanation:

you can see the square at the bottom. Around you can see 1 triangle in the front 2 on the sides and one in the back.

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|-3 + 15| what is the sum (answer) ? I think it is 12 but my friend thinks it is 18. Who is right?
Aliun [14]
I do believe it is 12 as well considering the fact that it's negative three and not positive. If it was a positive three then maybe it would be 18.
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3 years ago
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What is the sum of Triangle exterior angle sum with formula​
pentagon [3]

Answer:

Exterior angle = sum of opposite interior angles

Step-by-step explanation:

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2 years ago
Solve with solution...no spam answers pls
Agata [3.3K]
<span>Let's analyze Hannah's work, step-by-step, to see if she made any mistakes. 

</span>In Step 1, Hannah wrote \dfrac{d}{dx} (-3+8x) <span> as the sum of two separate derivatives </span>\dfrac{d}{dx}(-3)+ \dfrac{d}{dx} (8x) <span>using the </span><span>sum rule.
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This step is perfectly fine. 

In Step 2, \dfrac{d}{dx}(8x) was kept as it is, and \dfrac{d}{dx}(-3) was rewritten as 0 using the constant rule.Indeed, according to the constant rule, the derivative of a constant number is equal to zero.

This step is perfectly fine. 

In Step 3, \dfrac{d}{dx} (8x)  was rewritten as \dfrac{d}{dx}(8) \dfrac{d}{dx}(x) supposedly using the constant multiple rule.

The problem is that according to the constant multiple rule, \dfrac{d}{dx}(8x)&#10; should be rewritten as 8 \dfrac{d}{dx}(x) and not as \dfrac{d}{dx}(8)\dfrac{d}{dx}(x).  

<span>Therefore, Hannah made a mistake in this step.</span>
6 0
4 years ago
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N÷4=1225 what is the answer?
Vilka [71]
If you are looking for the value of N, multiply both sides by 4. The value of N is 4900.
7 0
3 years ago
If 40x = 400, then A. x equals 100. B. x equals 10. C. I equals 4. O D. x equals 1. E. requals 0 ).​
Brut [27]

Answer:

B- x= 10

Step-by-step explanation:

40x=400 ->  40 x 10= 400

8 0
3 years ago
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