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3 years ago

What is the minimum value of the function y=|x+3|-2 ?

Mathematics

1 answer:

lesya692 [45]3 years ago

6 0

Minimum value of the function is - 2

hope that helps

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28.52 is what percent of 77.5

I am Lyosha [343]

36.8%. divide 28.52 by 77.5 then multiply by 100

3 0

3 years ago

Victor drew trapezoid PQRS on a coordinate plane p(7,4) q(10,4) r(13,-1) s(8,-1) what is length in units of side ps

olga nikolaevna [1]

Answer:

PS= $\sqrt{26}units$

Step-by-step explanation:

Given : PQRS is a trapezoid on a coordinate plane P(7,4) Q(10,4) R(13,-1) S(8,-1).

To find:: Length of the side PS

Solution : Using the distance formula, we can find the length of the side PS, therefore

PS= $\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2}$

PS= $\sqrt{(-1-4)^{2}+(8-7)^2 }$

PS= $\sqrt{(-5)^2+(1)^2}$

PS= $\sqrt{25+1}$

PS= $\sqrt{26}units$

which is the required length of the side PS.

5 0

3 years ago

Wren recorded an outside temperature of -2 Fahrenheit at 8 a.m. When she checked the temperature again, it was 4 Fahrenheit at 1

castortr0y [4]

Rise over run. as time increases the temperature rises. starting at 8am and -2°f.
At 12pm the temperature rose to 4°f.
that's a difference of 4 hours and 6 degrees. for every hour, it rose 1.5 degrees. the slope is 1.5/1

7 0

3 years ago

If mZLKO = 72°, then what is mZJKH?<br> B<br> C<br> E<br> A<br> ►F<br> H Η<br> M

Shtirlitz [24]

Answer:

d-"5"_""__"_'uvyctxycuvycycycyv

6 0

3 years ago

Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui

Vesnalui [34]

<h3>The dimensions of the given rectangular box are:</h3><h3>L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box

= Area of the base + 4 x ( Area of the adjacent faces)

= S x S + 4 ( S x H) = S² + 4 SH ..... (1)

Also, Area of the box = S x S x H = S²H

⇒ S²H = 2000

$\implies H = \frac{2000}{S^2}$

Substituting the value of H in (1), we get:

$A = S^2 + 4 SH = S^2 + 4 S(\frac{2000}{S^2}) = S^2 + (\frac{8000}{S})\\\implies A = S^2 + (\frac{8000}{S})$

Now, to minimize the area put :

$(\frac{dA}{dS} ) = 0 \implies 2S - \frac{8000}{S^2} = 0\\\implies S^3 = 4000\\\implies S = 15.874 \approx 16 cm$

Putting the value of S = 15.874 cm in the value of H , we get:

$\implies H = \frac{2000}{S^2} = \frac{2000}{(15.874)^2} = 7.8937 cm$

Hence, the dimensions of the given rectangular box are:

L = 15.874 cm

B = 15.874 cm

H = 7.8937 cm

3 0

3 years ago