Answer:
65 units squared
Step-by-step explanation:
Why:area is base length times width. Considering what you gave me, 10 * 6.5 =65
Answer:
0.2071
Step-by-step explanation:
It looks like the graph is of the function ...
y = √(x +8) -2
We know that (-4, 0) is one point on the graph. The other point of interest is at x=0, where y = √8 -2 ≈ 0.8284.
The average rate of change on the interval is then ...
m = (0.8284 -0)/(0 -(-4)) = 0.2071
The average rate of change on the interval is about 0.2071.
_____
<em>Rougher estimate</em>
The graph goes through the points (-4, 0) and (1, 1), so has a slope of 1/5 = 0.2 on the interval [-4, 1]. We know the graph does not go through (0, 1), so the slope is not as high as 1/4 = 0.25. The curve is concave downward, so the average slope will be higher than 0.2, but we aren't sure how much higher.
A reasonable estimate of the rate of change on the interval is "a little more than 0.2, but less than 0.25."
Obtuse: b^2 + c^2 > a^2
Right: b^2 + c^2 = a^2
Acute: b^2 + c^2 < a^2
A^2 + B^2 + c^2 - 2bc*cosA
As (A), is an Obtuse cos A is Negative say 2bccosA = - k then;
a^2 = b^2 + c^2 + k
a^2 > b^2 + c^2
So, your Answer would be (B)
Hope this helps!!.!
Answer:
h = 24 ft
Step-by-step explanation:
A = 936 ft^2, b = 39 ft.
A = bh
Divide both sides by b:
h = A/b = 936 ft / 39 ft = 24 ft
Answer:
x - y = 118
Step-by-step explanation:
Since ∠ NOP and ∠ NOQ are complimentary then ∠ POQ = 90°
Since JOK is a straight line then
∠ JOP + ∠ POQ + ∠ QOK = 180 , that is
76 + 90 + y = 180
166 + y = 180 ( subtract 166 from both sides )
y = 14
Since MON is a straight line then
∠ MOK + ∠ KOQ + ∠ QON = 180, that is
x + 14 + 34 = 180
x + 48 = 180 ( subtract 48 from both sides )
x = 132
Thus
x - y = 132 - 14 = 118