What is the coefficient of x^2 in the expansion of (x+2)^3

Mathematics

1 answer:

goldenfox [79]3 years ago

3 0

(x+2)^3=x^3+2^3+3*x^2*2+3x*2^2=x^3+8+6x^2+12x

The coeficient of the x^2 is 6.

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3 years ago

Read 2 more answers

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True [87]

Answer:

∠ 4 = 140°

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ 4 is an exterior angle of the triangle, then

∠ 4 = ∠ 1 + ∠ 2 ( substitute values )

11x + 8 = 6x + 7 + 4x + 13

11x + 8 = 10x + 20 ( subtract 10x from both sides )

x + 8 = 20 ( subtract 8 from both sides )

x = 12

Then

∠ 4 = 11x + 8 = 11(12) + 8 = 132 + 8 = 140°

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12 × 12=144

12 × 20 = 240

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