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2 years ago

The sum of the measures of 2 angles is 90o. Angle C is 34o. Angle G is (3x-4)o. What is the value of x?

Mathematics

1 answer:

iragen [17]2 years ago

7 0

Answer:

d if "in2" means /2

Step-by-step explanation:

3x-4=90-34

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3/4(8x-4)=7x+2 This is a linear equation please help!

aleksandrvk [35]

Simplify the left hand side by multiplying the terms in the parenthesis by 3/4, i.e. divide them by 4 and multiply them by 3:

$\dfrac{3}{4}(8x-4)=7x+2 \iff 3(2x-1)=7x+2 \iff 6x-3 = 7x+2$

Subtract 6x from both sides:

$-3=x+2$

Subtract 2 to both sides:

$x=-5$

4 0

2 years ago

Read 2 more answers

The equation $(x - 7)^2 + (y + 13)^2 = 12$ represents a circle. What is its radius?

miskamm [114]

Answer:

Step-by-step explanation:

The standard equation of a circle is expressed as;

(x-a)²+(y-b)² = r² where;

(a, b) is the center of the circle

r is the radius of the circle

Given the equation (x - 7)^2 + (y + 13)^2 = 12

On comparing;

r² = 12

Take the square root of both sides

√r² = √12

r = √12

r = √4*3

r = 2√3

Hence the radius of the circle is 2√3

7 0

2 years ago

*Asymptotes* g(x) =2x+1/x-3 Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .