The answer is A. H(-4,2) I(-9,2) J(-9,-2) K(-2,-2)
Answer:
Interest earned = 2713.8
Explanation:
We will solve this problem on two steps:
1- get the final amount after three years
2- get the interest earned by subtracting the initial amount from the final one.
1- getting the final amount after 3 years:
The formula that we will use is as follows:
A = P (1 + r/n)^(nt)
where:
A is the final amount we want to calculate
P is the initial amount = 6300
r is the interest = 0.12
n is the number of compounds per year =12
t is time in years = 3
Substitute to get the final amount:
A = P (1 + r/n)^(nt)
A = 6300 (1 + 0.12/12) ^ (12*3)
A = 9013.8
2- getting the interest earned:
Interest earned = final amount - initial amount
Interest earned = 9013.8 - 6300
Interest earned = 2713.8
Hope this helps :)
1095 to the second power is what google told me!
Given:
A train travels 288 km at a uniform speed.
If the speed has been 4 km per hour more it would have taken one hour less for the same journey.
To find:
The initial speed of the train.
Solution:
Let x km/h be the initial speed on the train.
New speed of train = (x+4) km/h
We know that,

Time taken by the train initially to cover 288 km is
hours.
New time taken by the train to cover 288 km is
hours.
It is given that If the speed has been 4 km per hour more it would have taken one hour less for the same journey.





Splitting the middle term, we get




We know that the speed cannot be negative. So, the only possible value of x is 32.
Therefore, the speed of the train is 32 km/h.
Answer:
B. 5
Step-by-step explanation:
- |3 - 5 + 7|=
- |- 2 + 7 | =
- | 5 | =
- 5
<u>Answer is</u>: B. 5