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Dividing by 3,600
1
Determine the number of seconds you have. This information should be given, or it should be a figure you calculated yourself.
For example, you might be converting 2,400 seconds into hours.
ivide the number of seconds by 3,600. Note that there are 3,600 seconds in one hour.[1] So, if you have more than 3,600 seconds, your conversion will be greater than hour. If you have less than 3,600 seconds, your conversion will be a fraction of an hour.
3
Convert your decimal to minutes. This step is helpful if you are working with a number of seconds equal to less than an hour, so that you can gauge how long a certain decimal is. To convert the decimal to minutes, multiply it by 60.[2]
3200 seconds = 0.88888889 Hours
(rounded to 8 digits)
Answer:
Step-by-step explanation:
Use proportions to solve.
Corresponding sides have same ratio.
<u>Question 1</u>
- (6x + 3)/17 = (8x - 1)/21
- 21(6x + 3) = 17(8x - 1)
- 126x + 63 = 136x - 17
- 10x = 80
- x = 8
<u>Question 2</u>
- (x + 8)/21 = 32/28
- x + 8 = 21*8/7
- x + 8 = 24
- x = 24 - 8
- x = 16
Answer:
A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (3), B (4), C (2), and D (3). The grading system assigns quality points as follows: A: 4; B: 3; C: 2; D: 1; and F: 0. Find the student’s GPA for this semester. Round your answer to the nearest thousandth.
another way is
This is a weighted average question. You are going to "weight" each course by the number of credits it is worth and then divide by the total number of credits. In other words, you are going to multiply each grade (A=4, B=3) by the number of credits attached to that grade. This will ensure that the courses that have more credits count more in the overall average. Then you are going to divide by the total number of credits to get the overall GPA.
So,
(3*4 + 4*3 + 2 *2 + 3*1)/(3+4+2+3) = GPA
Step-by-step explanation:
bran-list please
Answer:
different
Step-by-step explanation:
different slopes gives one solution
same slopes with different constant has no solution
same slopes and constants has many solutions
