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serg [7]
3 years ago
8

Graph the first six terms of a sequence where a1 = −10 and d = 3.

Mathematics
1 answer:
Neko [114]3 years ago
8 0

notice the first term is -10, and the common difference is 3, so we add 3 to get the next term.

\bf \begin{array}{cccll}\stackrel{x}{n}&term&\stackrel{y}{value}\\\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\1&a_1&-10\\\\2&a_2&\stackrel{-10+3}{-7}\\\\3&a_3&\stackrel{-7+3}{-4}\\\\4&a_4&\stackrel{-4+3}{-1}\\\\5&a_5&\stackrel{-1+3}{2}\\\\6&a_6&\stackrel{2+3}{5}\end{array}

check the picture below.

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Part 2: Use the information provided to write the standard form equation of each circle
Archy [21]

Answer:

The answer to your question is below

Step-by-step explanation:

- The Standard form of the equation is

                  (x - h)² + (y - k)² = r²

4.

Center (8, -4)    r = \sqrt{118}

-Substitution

                 (x - 8)² + (y + 4)² =\sqrt{118}²                

-Result

                 (x - 8)² + (y + 4)² = 118

5.

Center (-10, 9)     r = \sqrt{37}

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                  (x + 10)² + (y - 9)² = \sqrt{37}²                

-Result

                  (x + 10)² + (y - 9)² = 37

6.-

Center (-8, 0)       r = 6

-Substitution

                  (x + 8)² + (y - 0)² = (6)²

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3 0
4 years ago
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What is the solution to the system
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See attachment file below.
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Hope it helped!

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4 years ago
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