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3 years ago

Why do you need distributive property

1 answer:

6 0

Because we have to evaluate was in the parenthesis and then solve it, then we need to remember to multiply first before going to the addition

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Under typical conditions, 1 <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D" id="TexFormula1" title="\frac{1}{2}" alt="\

damaskus [11]

Answer:

2 $\frac{1}{3}$ inches

Step-by-step explanation:

First, I would try to get the mixed numbers into improper fractions. Then, I try to make them have the same denominator so it is easier.

1 $\frac{1}{2}$ feet --- 2 inches

$\frac{3}{2}$ feet --- 2 inches

$\frac{6}{4}$ feet --- 2 inches

1 $\frac{3}{4}$ feet --- ? inches

$\frac{7}{4}$ feet --- ? inches

$\frac{7}{4}$ feet --- $\frac{7}{6}$ × 2 inches

= 2 $\frac{1}{3}$ inches

3 0

3 years ago

A local pizza shop has a membership program for frequent buyers. The membership

aalyn [17]

Answer: $48.

Step-by-step explanation:

Since each slice of pizza is $2 and Wyatt bought 14 slices of pizza, you would multiply 14 by 2 then add it onto the cost of the membership.

14 * 2 = 28

20 + 28 = 48

The monthly cost for 14 slices of pizza is $48.

6 0

3 years ago

Given the graph of a function f(x). What is f(-4)?

TEA [102]

Answer:

f (k)

Step-by-step explanation:

5 0

3 years ago

Find all solutions to the equation in the interval [0,2n) cos x = sin 2x

Serggg [28]

Answer:

$\huge\boxed{x\in\left\{\dfrac{\pi}{6};\ \dfrac{\pi}{2}\ \dfrac{3\pi}{2};\ \dfrac{5\pi}{6}\right\}}$

Step-by-step explanation:

$\cos x=\sin2x\qquad|\text{use}\ \sin\theta=2\sin\theta\cos\theta\\\\\cos x=2\sin x\cos x\qquad|\text{subtract}\ \cos x\ \text{from both sides}\\\\0=2\sin x\cos x-\cos x\\\\2\sin x\cos x-\cos x=0\qquad|\text{distribute}\\\\\cos x(2\sin x-1)=0\iff\underbrace{\cos x=0}_{(1)}\ \vee\ \underbrace{2\sin x-1=0}_{(2)}$

$(1)\\\cos x=0\Rightarrow x=\dfrac{\pi}{2}+k\pi;\ k\in\mathbb{Z}$

$(2)\\2\sin x-1=0\qquad|\text{add 1 to both sides}\\\\2\sin x=1\qquad|\text{divide sides by 2}\\\\\sin x=\dfrac{1}{2}\Rightarrow x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi$

$\text{From}\ (1)\ \text{and}\ (2)\ \text{we have}\\\\x=\dfrac{\pi}{2}+k\pi\ \vee\ x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi\\\\\text{We have the interval}\ x\in[0;2\pi).\ \text{Therefore the solution is:}\\\\x\in\left\{\dfrac{\pi}{6};\ \dfrac{\pi}{2}\ \dfrac{3\pi}{2};\ \dfrac{5\pi}{6}\right\}$

5 0

3 years ago

For what value of y does 125 = (StartFraction 1 Over 25 EndFraction) Superscript y minus 1?

timurjin [86]

Answer:

The Answer is D.) -1/2

Step-by-step explanation:

I just took the test and the answer was -1/2

5 0

3 years ago

Read 2 more answers