The smallest area is:
A2 = (1/4) * (A1)
Substituting:
A2 = (1/4) * (12)
A2 = 3 feet ^ 2
Since both are squares then:
L2 = root (3)
L1 = root (12)
The relationship is:
L2 / L1 = (root (3)) / (root (12))
Rewriting:
L2 / L1 = (root (3)) / (root (3 * 4))
L2 / L1 = (root (3)) / (2raiz (3))
L2 / L1 = 1/2
Answer:
The fraction of the side length of the larger rug with a side length of the smaller one is:
L2 / L1 = 1/2
Answer:

Step-by-step explanation:
We have to simplify the original function using partial fraction, hence:

![From\ Laplace\ inverse:\\\\But\ L^{-1}[\frac{1}{s-a} ]=e^{at}\\\\Hence:\\\\L^{-1} [\frac{5s}{s^2+3s-4}]=L^{-1}[\frac{1}{s-1} ]+L^{-1}[\frac{4}{s+4} ]=e^{t}+4e^{-4t}\\\\L^{-1} [\frac{5s}{s^2+3s-4}]=e^{t}+4e^{-4t}](https://tex.z-dn.net/?f=From%5C%20Laplace%5C%20inverse%3A%5C%5C%5C%5CBut%5C%20L%5E%7B-1%7D%5B%5Cfrac%7B1%7D%7Bs-a%7D%20%5D%3De%5E%7Bat%7D%5C%5C%5C%5CHence%3A%5C%5C%5C%5CL%5E%7B-1%7D%20%5B%5Cfrac%7B5s%7D%7Bs%5E2%2B3s-4%7D%5D%3DL%5E%7B-1%7D%5B%5Cfrac%7B1%7D%7Bs-1%7D%20%5D%2BL%5E%7B-1%7D%5B%5Cfrac%7B4%7D%7Bs%2B4%7D%20%5D%3De%5E%7Bt%7D%2B4e%5E%7B-4t%7D%5C%5C%5C%5CL%5E%7B-1%7D%20%5B%5Cfrac%7B5s%7D%7Bs%5E2%2B3s-4%7D%5D%3De%5E%7Bt%7D%2B4e%5E%7B-4t%7D)
Hello there.
<span>
If p and q are nonzero integers, which pair of points must lie in the same quadrant?
</span>
<span>B. (p, q) and (2p, 2q)
</span>
X=1
8-2x=-8x+14
-2x=-8x+6
6x=6
x=1
Given:
Machine dispenser
Average = 600 mL soda to every glass
Volumes recorded in one day (random sampling)
600.15
599.92
599.85
599.92
599.81
600.14
600.04
599.98
Average = (sum of the volumes)/(number of readings)
= 4799.81/8
Average = 599.976 mL
Therefore there is sufficient evidence to conclude that the average volume of soda dispenser is different from 600 mL.