2. The median for the data is the correct answer
The product could be either less than or greater than 67,124.
If you multiplied by a negative number, you would get a negative number, which is less than a positive number such as 67,124.
If you multiplied by zero, you would get zero, which is less than a positive number such as 67,124.
If you multiplied by one, you would get 67,124, which is equal to 67,124 since they are the same number.
If you multiplied by a positive number less than one, you would get a positive number greater than zero and less than 67,124.
If you multiplied by a positive number greater than one, you would get a positive number greater than 67,124.
Let's start by declaring our varibles.
x = number of lawns Mr. Brust mowed
y = total amount of money Mr. Brust made
Let's create our equation.
y = 15x + 55
For part b, we can plug 800 in for y.
800 = 15x + 55
Subtract 55 from both sides.
745 = 15x
Divide both sides by 15
50 = x. Note, I rounded the answer to the nearest integer.
For part c, we can plug 13 in for x.
y = 15(13) + 55
Simplify the right side of the equation.
y = 250
Answer:
2 trees
Step-by-step explanation:
Since the city is planting a tree every 20 feet across Dayton Avenue, then we need to find the length of the side that is on Dayton Avenue.
We are missing 3 sides to this. But it's extremely important to note that the side adjacent to Dayton Avenue is the same length as the other missing two sides combined. This is because both of these lengths contain the 1 feather and 2 feather mark - these signify congruence.
This means that the side lengths of both of them combined will be 
This means the side adjacent to Dayton Avenue is
feet long.
Now that we know that the side is 57 feet long, we have to divide this by 20, as a tree is being placed every 20 feet. If we get a decimal, we will have to round down because it gets planted only, and only if, 20 more feet has been accomplished. If we are a fraction of the way there, a tree doesn't get planted.
Rounding down gets us 2.
Hope this helped!
