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il63 [147K]
3 years ago
13

5.) What is the quotient of 15.26 and 3.5?

Mathematics
2 answers:
laiz [17]3 years ago
6 0

Answer:

4.36

Step-by-step explanation:

Quotient means to divide, so you divide 15.26 by 3.5. 15.26/3.5 is 4.36.

elena55 [62]3 years ago
3 0

Answer:

I got 18.26

Step-by-step explanation:

Added them up

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Let x be the number of boys in a family of 4 children. Determine the values of the variable x. please answer.
Morgarella [4.7K]
There could be 1,2,3,4, or 5
3 0
3 years ago
Glenn needs to cut pieces of a lanyard that are each 1 meter long to make lanyard key chains. If he has 3 pieces of lanyard that
Novosadov [1.4K]

Answer:

30

Step-by-step explanation:

3 pieces each 1 dekameter long

1 dekameter = 10 meters

Convert dekameters to meters

3 pieces each 10 meters long

Multiply

Glenn has 30 meters of lanyard

Divide

He can cut 30 1-meter pieces

Hope this helps :)

3 0
3 years ago
The problem
Afina-wow [57]

Answer:

Step-by-step explanation:

In the given division, when 24.725 is divided by 215,

Step 1 is the wrong step.

Quotient in first step will be 0.1 .

Part C.

215) 24.725 (0.115

      <u> 215</u>

          322

          <u>215</u>

           1075    

           <u>1075</u>

                0

Therefore, the correct way to divide should be as agove.

Quotient after division should be 0.115.

6 0
3 years ago
A giraffe can run about 14 meters per second. Find it's speed in miles per hour
Inga [223]
(14 meter/sec) x (1 mile/1609.344 meter) x (3,600 sec/hour) =

                         (14 x 3600) / (1609.344) = <em>31.32 mile/hour  </em>(rounded)
4 0
3 years ago
Ninety-one percent of products come off the line within product specifications. Your quality control department selects 15 produ
Allisa [31]

Answer:

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

Step-by-step explanation:

There is a random binomial variable X that represents the number of units come off the line within product specifications in a review of n Bernoulli-type trials with probability of success 0.91. Therefore, the model is {15 \choose x} (0.91) ^ {x} (0.09) ^ {(15-x)}. So:

P (X < 9) = 1 - P (X \geq 9) = 1 - [{15 \choose 9} (0.91)^{9}(0.09)^{6}+...+{ 15 \choose 15}(0.91)^{15}(0.09)^{0}] = 0.0002

P (X < 10) = 1 - P (X \geq 10) = 1 - [{15 \choose 10}(0.91)^{10}(0.09)^{5}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0013

P (X < 11) = 1 - P (X \geq 11) = 1 - [{15 \choose 11}(0.91)^{11}(0.09)^{4}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0082

P (X < 12) = 1- P (X \geq 12) = 1 - [{15 \choose 12}(0.91)^{12}(0.09)^{3}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0399

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

8 0
3 years ago
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