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3 years ago

What is the exact length of AB? (photo below)

Mathematics

2 answers:

yawa3891 [41]3 years ago

5 0

I don't know an equation so don't do rate this...but if it were me, I would guess between 6(pi) or 8(pi)

olga_2 [115]3 years ago

3 0

As you can see, the central angle for the arcAB is 270°, whilst the radius is 4 units long.

$\bf \textit{arc's length}\\\\
s=\cfrac{\theta \pi r}{180}~~
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
\theta =270\\
r=4
\end{cases}\implies s=\cfrac{(270)(\pi )(4)}{180}\implies s=6\pi$

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krok68 [10]

Answer:

$f (0.8) = 22.3607$ and $P_{2} (0.8) = 22.300$ .

Step-by-step explanation:

According to the statement, $f (x) = \frac{20}{\sqrt{x}}$ and $P_{2}(x) = 20 - 10 (x-1) + 7.5 (x-1) ^ 2$ . Based on these definitions, at $x=0.8$ produce:

$f (0.8) = \frac{20}{\sqrt {0.8}} = 22.3607$ . On the other hand, you have to:

$P_{2} (0.8) = 20 - 10 (0.8 -1) +7.5 (0.8 -1)^2$

$P_{2} (0.8) = 20 - 10 (-0.2) +7.5 (-0.2)^2 = 22.300$

Then, it can be affirmed that $f (0.8) = 22.3607$ and $P_{2} (0.8) = 22.300$ .

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4 years ago

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Setler79 [48]

Answer:

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Answer:

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Step-by-step explanation:

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2 years ago

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