Answer: 12πins.
Step-by-step explanation:
Since the area if a circle = πr²
From the question
Area of the circle = 36πins²
To find the circumference of the circle, we need to find the common radius of the circle and this could be achieved from the area of the circle given above.
πr² = 36π, solving this gives. Divide through by π
r² = 36
r = +/-√36
= +/-6
Now to find the circumference of the circle, we substitute for r in the formula below.
Circumstances = 2πr
= 2 ×π × 6
= 12πins.
Answer:
C. 9
Step-by-step explanation:
Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)
Answer:
<em>A=3 and B=6</em>
Step-by-step explanation:
<u>Increasing and Decreasing Intervals of Functions</u>
Given f(x) as a real function and f'(x) its first derivative.
If f'(a)>0 the function is increasing in x=a
If f'(a)<0 the function is decreasing in x=a
If f'(a)=0 the function has a critical point in x=a
As we can see, the critical points may define open intervals where the function has different behaviors.
We have
Computing the first derivative:
We find the critical points equating f'(x) to zero
Simplifying by -6
We get the critical points
They define the following intervals
Thus A=3 and B=6
Answer:
3 zeros
Step-by-step explanation:
4*500=2000
<span>(a.)
Let's say α is the angle that subtends from the top of the screen to horizontal eye-level.
Let β be the angle that subtends from the bottom of the screen to horizontal eye-level.
tanα = (22 + 10 - 4) / x = 28/x
α = arctan(28/x)
tanβ = (10 - 4) / x = 6/x
β = arctan(6/x)
Ɵ = α - β
Ɵ = arctan(28/x) - arctan(6/x)
(b.)
tanƟ = tan(α - β) = (tanα - tanβ) / (1 + tanα tanβ)
tanƟ = (28/x - 6/x) / [1 + (28/x)(6/x)]
tanƟ = (22/x) / [1 + (168/x²)]
tanƟ = 22x / (x² + 168)
Ɵ = arctan[22x / (x² + 168)]</span>
