Answer:
It is a trapezium, I guess
Step-by-step explanation:
To know more see the picture attached
It’s bevause you can see what you are doing instead of doing it all of your head which could get messed up.
Answer:
a.
R-------8/38--------RR
R------9/39--------B-------13/38-------RB
G------17/38--------RG
R-------9/38--------BR
B--------13/39------B-------12/38-------BB
G-------17/38-------BG
R-----9/38--------GR
G---------17/39-------B------13/38-------GB
G------16/38-------GG
b).
- 9 ways
- ways you can select 1 blue are; RB,BR,BG,GB
RB=9/39 × 13/38=3/38
BR= 13/39 × 9/38 =3/38
BG= 13/39 × 17/38=17/114
GB= 17/39 × 13/38=17/114
=3/38 +3/38+17/114+ 17/114 =26/57
- Probability of selecting 2 red markers= RR = 9/39 × 8/38 =12/247
- Probability of selecting a green marker and then a red marker= GR= 17/39×9/38 =51/494
9514 1404 393
Answer:
$2.50
Step-by-step explanation:
The question asks for the total cost of a notebook and pen together. We don't need to find their individual costs in order to answer the question.
Sometimes we get bored solving systems of equations in the usual ways. For this question, let's try this.
The first equation has one more notebook than pens. The second equation has 4 more notebooks than pens. If we subtract 4 times the first equation from the second, we should have equal numbers of notebooks and pens.
(8n +4p) -4(3n +2p) = (16.00) -4(6.50)
-4n -4p = -10.00 . . . . . . . . . . . simplify
n + p = -10.00/-4 = 2.50 . . . . divide by the coefficient of (n+p)
The total cost for one notebook and one pen is $2.50.
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<em>Additional comment</em>
The first equation has 1 more notebook than 2 (n+p) combinations, telling us that a notebook costs $6.50 -2(2.50) = $1.50. Then the pen is $2.50 -1.50 = $1.00.
One could solve for the costs of a notebook (n) and a pen (p) individually, then add them together to answer the question. We judge that to be more work.
