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Alchen [17]
3 years ago
12

Show all your work to receive full credit for this problem. Solve the system of equations using the elimination method. 2a + 3b

= -1 3a + 5b = -2
Mathematics
1 answer:
Sindrei [870]3 years ago
8 0

Given equations are;<span>
2a + 3b = -1   ..................equation 1
3a + 5b = -2  ....................equation 2</span>

Now multiply equation 1 with (-3)

The equation will be;

-6a -9b = 3 …………………..equation 3

Now multiply equation 2 with (2)

The equation will be;

6a + 10b = -4 ……………..equation 4

Now add equation 3 and equation 4

-6a – 9b = 3

<span>6a  + 10b = -4</span>

<span>------------------------------</span>

0a + b = -1

b = -1

Now put the value of b in equation 1

2a + 3(-1) = -1

2a -3 = -1

2a = -1+3

2a = 2

a=1

Thus the solution is (a,b) = (1,-1)

<span>
</span>

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A bank offers all savings accounts 5% interest compounded annually. If one account has a principal of $100 and another
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From the calculation for both the accounts, it is clear that both the account double in the same time period of 14 years 26 days .

Step-by-step explanation:

Given as :

The principal for the first account = p = $100

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The account gets double , so, Amount = A = $200

Let the time after which account gets double = t years

So<u>, From Compound Interest method</u>

Amount = Principal × (1+\dfrac{\trxtrm rate}{100})^{\textrm time}

As amount is double its principal

So, A = 2 × $100 = $200

Or, A = p × (1+\dfrac{\trxtrm r}{100})^{\textrm t}

Or, $200 = $100 × (1+\dfrac{\trxtrm 5}{100})^{\textrm t}

Or, \dfrac{200}{100} = (1.05)^{\textrm t}

Or, 2 = (1.05)^{\textrm t}

Taking Log both side

Log_{10}2 = Log_{10}(1.05)^{t}

Or, 0.3010 = t Log_{10}1.05

Or, 0.3010 = t × 0.0211

∴ t = \dfrac{0.3010}{0.0211}

I.e t = 14.26

So, The time period to get account double is 14 years 26 days

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Amount = Principal × (1+\dfrac{\trxtrm rate}{100})^{\textrm time}

Or, A = p × (1+\dfrac{\trxtrm r}{100})^{\textrm t}

As amount is double its principal

So, A = 2 × $1000 = $2000

Or, $2000 = $1000 × (1+\dfrac{\trxtrm 5}{100})^{\textrm t}

Or, \dfrac{2000}{1000} = (1.05)^{\textrm t}

Or, 2 = (1.05)^{\textrm t}

Taking Log both side

Log_{10}2 = Log_{10}(1.05)^{t}

Or, 0.3010 = t Log_{10}1.05

Or, 0.3010 = t × 0.0211

∴ t = \dfrac{0.3010}{0.0211}

I.e t = 14.26

So, The time period to get account double is 14 years 26 days

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