Hi there!
The general formula of A line in slope-intercept form is the following:

In this formula m represents the slope of the line. Therefore, we can conclude that m = 2/5.

We also know that the line passes through the point (-3, -1) and we can therefore substitute this coordinate into the formula of the line.
x = -3 and y = -1

Multiply first.

And finally add 1 1/5 to both sides of the equation.

We can now switch sides.

Now we've found our value of n, which we can substitute into the formula of our line. Hence, in slope-intercept form, we find the following:
Two angles are said to be complementary, if the sum of the measures of the to angles is equal to 90 degrees.
Thus, given that HFG is complementary to ACB, them mHFG + mACB = 90 degrees.
From the figure, given that the line from point F meats line CE at point P, then HFG = CFP.
But mCFE = 90 degrees and mCFE = mCFP + mPFE
Also PFE = DFH
Thus, mCFE = mCFP + mPFE = mHFG + mDFH = 90 degrees
Recall that mHFG + mACB = 90 degrees
Thus, mHFG + mACB = mHFG + mDFH
Therefore, mACB = mDFH.
Answer:
6
Step-by-step explanation:
2y x 3x
The equation for a hyperbola is (x-h)/a - (y-k)/b = 1
Or (y-k)/a - (x-h)/b = 1
h represents the x value of the coordinate
k value represents the y value of the coordinate
together they represent a point, which is the center
So (h,k) is (x,y)
The asymptote is y-k = +/- b/a (x-h)
The transverse is the line that goes through the hyperbola.
Answer:
157 in
Step-by-step explanation:
2x3.14x25 = 157 in