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Trava [24]
3 years ago
13

Find the slope (rate of change) for the following table

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
5 0

Answer:

Slope: 0.3

Step-by-step explanation:

divide 3 by 10 then you got your answer

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Find dy/dx of y=csc(square root of x)
Vitek1552 [10]

Answer:

y' = -\dfrac{\cot x \csc x}{2 \sqrt{x}}

Step-by-step explanation:

y = csc x

y' = -cot x csc x

y = \csc \sqrt{x}

y' = \dfrac{d}{dx} [\csc \sqrt{x}]

y' = (-\cot x \csc x) \dfrac{d}{dx} \sqrt{x}

y' = (-\cot x \csc x) \dfrac{d}{dx} x^{\frac{1}{2}}

y' = (-\cot x \csc x) \dfrac{1}{2} x^{-\frac{1}{2}}

y' = -\dfrac{\cot x \csc x}{2 \sqrt{x}}

5 0
2 years ago
Consider the possible solution to each inequality. Choose Yes or No for each question.
ZanzabumX [31]

Answer:

a. No

b. Yes

c. No

d. Yes

e. Yes

Step-by-step explanation:

a. 8 + 13 = 21. No

b. -6 - 10 = -4. Yes

c. 6 × 4.6 = 27.6. No

d. 15 × 3.9 = 58.5. Yes

e. -6 × (-5) = 30. Yes

3 0
2 years ago
Can you answer this for me?
zvonat [6]

Answer:

what

Step-by-step explanation:

there is no attachment

3 0
3 years ago
Read 2 more answers
You have an object with a mass of 5 kg. If it has a velocity of 4.7 m/s, what distance will the object travel if 98 newtons are
professor190 [17]

69,420 ------------------------------------------------------------------------

6 0
2 years ago
Rewrite the function in standard form, intercept form, find the vertex, find the y-intercept, and find the x-intercepts.
jasenka [17]

Answer:

We have the function, f(x)=(x+3)^{2}-4

On simplifying, we get,

f(x)=x^2+6x+9-4

i.e. f(x)=x^2+6x+5

Thus, the standard form of the function is f(x)=x^2+6x+5.

Now, the factors of the given functions are (x+1) and (x+5).

<em>Since, the intercept form of the function is the factored form of the function.</em>

So, we have, intercept form of the function is f(x)=(x+1)(x+5).

Now, we know that,

Value of x-coordinate of the vertex is \frac{-b}{2a} i.e. \frac{-6}{2\times 1} i.e. \frac{-6}{2} i.e. x= -3

Then, f(-3)=(-3)^2+6\times (-3)+5 i.e. f(-3)=9-18+5 i.e. f(-3)=-4

So, the vertex of the function is (-3,-4).

Further, we know that,<em> 'the y-intercept of a function is the point where the function crosses y-axis'.</em>

So, when x=0, we have, f(0)=0^2+6\times 0+5 i.e. f(0) = 5

Thus, the y-intercept is (0,5)

Also, <em>'the x-intercept of a function is the point where the function crossese x-axis'.</em>

Then, for f(x)=0, we have 0=x^2+6x+5 i.e. 0=(x+1)(x+5) i.e. x= -1 and x= -5

Thus, the x-intercept are (-1,0) and (-5,0).

8 0
3 years ago
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