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77julia77 [94]
3 years ago
13

An experiment reported in Popular Science compared fuel economies for two types of similarly equipped diesel mini trucks. Let us

suppose that 11 Volkswagen and 9 Toyota trucks were tested in 90- kilometers per-hour steady-paced trials. If the 11 Volkswagen trucks averaged 16 kilometers per liter with a standard deviation of 1.0 kilometer per liter and the 9 Toyota trucks averaged 11 kilometers per liter with a standard deviation of 0.8 kilometer per liter. Assume that the distances per liter for the truck models are approximately normally distributed with equal variances. Construct a 98% confidence interval for ????????1/????????2, where ????????1 and ????????2 are, respectively, the standard deviations for the distances traveled per liter of fuel by the Volkswagen and Toyota mini trucks.
Mathematics
1 answer:
expeople1 [14]3 years ago
6 0
I don’t really understand this question so I will try to figure it out later
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A study found that a 95% confidence interval for the mean μ of a particular population was computed from a random sample of 1200
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Answer:

95% confidence interval for the mean μ is (6,14)

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Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given random sample 'n' = 1200

95% confidence interval for the mean μ is determined by

        (x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} +Z_{\alpha } \frac{S.D}{\sqrt{n} } )

Level of significance = 95% 0r 0.05

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95% of confidence intervals are

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                  ( 10 -4 , 10+4)

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