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77julia77 [94]
3 years ago
13

An experiment reported in Popular Science compared fuel economies for two types of similarly equipped diesel mini trucks. Let us

suppose that 11 Volkswagen and 9 Toyota trucks were tested in 90- kilometers per-hour steady-paced trials. If the 11 Volkswagen trucks averaged 16 kilometers per liter with a standard deviation of 1.0 kilometer per liter and the 9 Toyota trucks averaged 11 kilometers per liter with a standard deviation of 0.8 kilometer per liter. Assume that the distances per liter for the truck models are approximately normally distributed with equal variances. Construct a 98% confidence interval for ????????1/????????2, where ????????1 and ????????2 are, respectively, the standard deviations for the distances traveled per liter of fuel by the Volkswagen and Toyota mini trucks.
Mathematics
1 answer:
expeople1 [14]3 years ago
6 0
I don’t really understand this question so I will try to figure it out later
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Can someone please help me.
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Given 
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Solution:
Method: Evaluate some of the values, for each function.  A function with ANY value not matching the given f(n) values will be rejected.

N=1, f(n)=4
f(1)=4-3(1-1)=4
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N=2, f(n)=12
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f(1)=4(3^(2-1)=4*3^1=4*3=12
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Will need to check one more to be sure
N=3, f(n)=3
[rejected]
[rejected]
f(3)=4(3^(n-1))=4(3^(3-1))=4(3^2)=4*9=36   [Good]
[rejected]

Solution: f(n)=4(3^(n-1))










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