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Mila [183]
3 years ago
8

 1. Find the VALUE of 7x + 3y, when x = 12 and y = -6.

Mathematics
2 answers:
denis23 [38]3 years ago
8 0

Answer:

1.7(12) + 3(-6) = 84 - 18 = 66

slavikrds [6]3 years ago
3 0
Answer:
1. 66
2. 3.87 x 10^-5
3. 81.67
4. 7y - 19

Explanation:

7(12) + 3(-6)
= 84 - 18
= 66

2. 0.0000387 = 3.87 x 10^-5

3.
Area = 3.14 x (5.1)^2
= 81.67cm^2

4.
6(2y - 3) - 5(y + 1)
= 12y - 18 - 5y - 1
= 7y - 19
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3 years ago
What is the solution to the system x+y=10 3y=-3x+30<br><br> PLEASE helpppp
choli [55]

Answer:

Step-by-step explanation:

x+y=10

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6 0
3 years ago
BRAINLIEST ASAP! PLEASE HELP ME :)
harkovskaia [24]

Answer:

○\displaystyle -\frac{2\sqrt{3}}{3}\:[or\:-\frac{2}{\sqrt{3}}]

Step-by-step explanation:

You have to know the Unit Circle on this one. So, to start off, in the degree-angle range from 180° - 270° [Quadrant III], you must figure out the cosine value that gives you −½, and according to the graph, <em>theta</em><em> </em>will be represented as 240°. So, now that we have our <em>θ</em>, looking at the <em>y-value</em><em> </em>240°, since we want the <em>cosecant</em><em> </em>function, all we have to do is take the multiplicative inverse of \displaystyle -\frac{\sqrt{3}}{2},which gives you \displaystyle -\frac{2\sqrt{3}}{3}.

Extended Information

\displaystyle y-coordinate → sin\:θ \\ x-coordinate → cos\:θ

\displaystyle -\frac{2\sqrt{3}}{3} = [-\frac{\sqrt{3}}{2}]^{-1}

I am joyous to assist you anytime.

5 0
4 years ago
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Kisachek [45]
Your function is:

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7 0
3 years ago
Read 2 more answers
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