Answer:
P(t) = 12e^1.3863k
Step-by-step explanation:
The general exponential equation is represented as;
P(t) = P0e^kt
P(t) is the population of the mice after t years
k is the constant
P0 is the initial population of the mice
t is the time in months
If after one month there are 48 population, then;
P(1) = P0e^k(1)
48 = P0e^k ...... 1
Also if after 2 months there are "192" mice, then;
192 = P0e^2k.... 2
Divide equation 2 by 1;
192/48 = P0e^2k/P0e^k
4 = e^2k-k
4 = e^k
Apply ln to both sides
ln4 = lne^k
k = ln4
k = 1.3863
Substitute e^k into equation 1 to get P0
From 1, 48 = P0e^k
48 = 4P0
P0 = 48/4
P0 = 12
Get the required equation by substituting k = 1.3863 and P0 = 12 into equation 1, we have;
P(t) = 12e^1.3863k
This gives the equation representing the scenario
1. x = 2
2. x = 9
3. a = 3
4. x = 13
5. c = 3
6. s = 3
7. x = 7
8. c = 0
9. b = 1
10. c = 4
11. x = 4
12. x = 8
13. x = 12
14. y = 10
15. x = 11
16. x = 10
17. x = 6
18. x = 11
9514 1404 393
Answer:
(-1/4, 2)
Step-by-step explanation:
Substitute the given information into the equation and solve for y.
3y +4(-1/4) = 5
3y -1 = 5 . . . . . . simplify
3y = 6 . . . . . . . . add 1
y = 2 . . . . . . . . . divide by 3
The point is (-1/4, 2).
Answer: (b) x = -2/3
<u>Step-by-step explanation:</u>
The vertical asymptote is the restriction on x.
The denominator cannot be equal to zero so that it the restriction.
Set the denominator equal to zero and solve for x to find the asymptote.
3x + 2 = 0
3x = -2
x = -2/3
Step-by-step explanation:
the positive integer numbers that are divisible by 7 are an arithmetic sequence by always adding 7 :
a1 = 7
a2 = a1 + 7 = 7+7 = 14
a3 = a2 + 7 = a1 + 7 + 7 = 7 + 2×7 = 21
...
an = a1 + (n-1)×7 = 7 + (n-1)×7 = n×7
the sum of an arithmetic sequence is
n/2 × (2a1 + (n - 1)×d)
with a1 being the first term (in our case 7).
d being the common difference from term to term (in our case 7).
how many terms (what is n) do we need to add ?
we need to find n, where the sequence reaches 200.
200 = n×7
n = 200/7 = 28.57142857...
so, with n = 29 we would get a number higher than 200.
so, n=28 gives us the last number divisible by 7 that is smaller than 200 (28×7 = 196).
the sum of all positive integers below 200 that are divisible by 7 is then
28/2 × (2×7 + 27×7) = 14 × 29×7 = 2,842
