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Dvinal [7]
3 years ago
13

Hiii please help if you give a correct answer i’ll give brainliest thanks!

Mathematics
1 answer:
vovangra [49]3 years ago
5 0
Answer: B and D

Explanation:
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An arithmetic sequence begins as follows: a1=13 a2=19 Which of the following gives the definition of its nth term?
Otrada [13]

Answer:

the nth term of the sequence is a_n=6n+7

Step-by-step explanation:

Given : An arithmetic sequence begins as follows: a_1=13, a_2=19

To find : Which of the following gives the definition of its nth term?

Solution :

The nth term of the A.P is a_n=a+(n-1)d

The first term is a=a_1=13

The common difference is d=a_2-a_1

d=19-13=6

Substitute in the formula,

a_n=13+(n-1)6

a_n=13+6n-6

a_n=6n+7

Therefore, the nth term of the sequence is a_n=6n+7

5 0
3 years ago
if two fractions have the same denominator but different numerators which fraction is greater? Give an example.
krek1111 [17]
The larger fractron will be the fraction with the greater numerator.
ex. 4/5 is greater than 2/5
7 0
3 years ago
Read 2 more answers
What are the roots of the polynomial equation?
Andreas93 [3]

Answer:

The roots of the polynomial equation in this case would be the intersection of the 2 polynomial functions.  which are at  x = 4 and x = -3

Step-by-step explanation:

The roots are found by finding the x-values of the intersections of these two cubic polynomial functions.

We could try solving algebraically, but you have the graph.

6 0
4 years ago
Write the real number 12 as a complex number
valkas [14]

A complex fraction is. Fraction at a whole number

7 0
3 years ago
What is the sum of the geometric series
Sergio039 [100]
Answer: 2343 / 256

Explanation

I will do this for you in two forms: 1) adding each term, and 2) using the general formula for the sum of geometric series.

1) Adding the terms:

 4
∑ 3 (3/4)^i = 3 (3/4)^0 + 3 (3/4)^1 + 3 (3/4)^2 + 3 (3/4)^3 + 3 (3/4)^4
i=0

= 3 + 9/4 + 27/16 + 81/64 + 243/256 = [256*3 + 27*16 + 64*9 + 4*81 + 243] / 256 =

= 2343 / 256

2) Using the formula:

n-1
∑ A (r^i) = A [1 - r^(n) ] / [ 1 - r]
i=0

Here n - 1 = 4 => n = 5

r = 3/4

A = 3

Therefore the sum is 3 [ 1 - (3/4)^5 ] / [ 1 - (3/4) ] =

= 3 [ 1 - (3^5) / (4^5) ] / [ 1/4 ] = 3 { [ (4^5) - (3^5) ] / (4^5) } / {1/4} =

= (3 * 781) / (4^5) / (1/4) =  3 * 781 / (4^4) = 2343 / 256

So, no doubt, the answer is 2343 / 256
5 0
4 years ago
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