Answer:
45,000 codes
Step-by-step explanation:
We can define that "digits" are defined to symbols 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9. There are a total of ten digits.
The problem indicates that the first digit cannot be zero, this means that there are 9 options in the first digit of the code.
For the second, third and fourth digits of the code there is no restriction, so there are 10 options for each.
For the fifth digit of the code, we can choose any even digit, so we have 5 options.
This means that there is a total of
9 * 10 * 10 * 10 * 5 = 45,000
