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4 years ago

Factor each expression. Problem: g^2 - 9 Answer: (g + 3) (g - 3)

1 answer:

8 0

$g^2-9$
The 9 here could be rewritten as 3^2,

$g^2-3^2$
Factor the difference in these two squares, you get
$(g-3)(g+3)$

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Solve the Solve the simultaneous equations 2x+3y=20 x+5y=31

zlopas [31]

Answer:

$x = 1$ and $y = 6$

Step-by-step explanation:

Given

$2x + 3y = 20$

$x + 5y = 31$

Required

Solve for x and y

Make x the subject in the second equation

$x = 31 - 5y$

Substitute 31 - 5y for x in $2x + 3y = 20$

$2(31 - 5y) + 3y = 20$

$62 - 10y + 3y = 20$

$62 - 7y = 20$

Collect like terms

$-7y = 20 - 62$

$-7y = - 42$

Solve for y

$y = \frac{-42}{-7}$

$y = 6$

Substitute 6 for y in $x = 31 - 5y$

$x = 31 - 5 * 6$

$x = 31 - 30$

$x = 1$

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3 years ago

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Sever21 [200]

The answer is True !!!!

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3 years ago

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Anastasy [175]

Answer:

150 offices.

Step-by-step explanation:

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3 years ago

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motikmotik

Answer: No. Equations even if it is paired. So on. It can only have one solution. Although this is only for a system of equations.

A linear can have two. It just depends on what the problem is.

Step-by-step explanation:

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Rama09 [41]

4(2)+1/3(3^2) = 11
Hope you got this

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3 years ago