Can anyone give me formula to solve these problems?

Mathematics

1 answer:

Free_Kalibri [48]3 years ago

8 0

Which problems send them to me I’ll answer them as soon as possible

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Find the area of the shaded regions? plss helppp

gregori [183]

Answer:

Larger shaded area = 48pi m^2 and

the small circle has area 4pi m^2.

If you require the as decimal values they are

150.80 m^2 and 12.57 m^2 to the nearest hundredth.

Step-by-step explanation:

The area of the whole circle = pi r^2 = pi 8^2 = 64pi.

The area of the middle sized circle = pi 4*2 = 16pi.

So the area of the larger shaded region

= 64pi - 16pi = 48pi m^2.

The area of the small circle = pi r^2 = 2^2 pi = 4pi m^2.

3 0

3 years ago

Me dicen la respuesta porfa

vovikov84 [41]

Answer:

la respuesta es la tercera abajo

Step-by-step explanation:

7 0

3 years ago

(PLZ HELP STAT) The lengths of three sides of a trapezoid are shown below:

balandron [24]

Hey there :)

The perimeter formula of a trapezium is:
P = a + b + c + d ( adding all sides )

Perimeter is given : P = 17z³ + 60z² + 2z - 5

Part A :

Total lengths of sides 1, 2 and 3 will be just adding the given lengths :
1 → 16z² - 4z + 2
2 → 7z² - 2z + 21
3 → 18z² - 3z + 2

side 1 + side 2 + side 3
( 16z² - 4z + 2 ) + ( 7z² - 2z + 21 ) + ( 18z² - 3z + 2 )

Combine like terms together:

16z² + 7z² + 18z² - 4z - 2z - 3z + 2 +21 + 2
41z² - 9z + 25

Part B:

Length of 4th side will be the total perimeter minus the total length of sides 1, 2 and 3:

( 17z³ + 60z² + 2z - 5 ) - ( 41z² - 9z + 25 )

Combine like terms

17z³ + 60z² - 41z² + 2z + 9z - 5 - 25
17z³ + 19z² + 11z - 30

Part C:

Addition of polynomials result in polynomials as well as subtraction of polynomials result in polynomials.

Therefore, this polynomial is closed under addition and subtraction.