If you convert feet to inches, 1 ft = 12 in
2 feet * 12 inches = 24 in
That means 2 ft is greater than 23 in.
3 * ln 4x = 13
<span><=> </span>
<span>ln 4x = 13/3 </span>
<span><=> </span>
<span>4x = e^(13/3) </span>
<span><=> </span>
<span>x = e^(13/3) / 4 </span>
<span><=> </span>
<span>x ~ 19.05 </span>
Answer: mx+2ny+z −zy4−zx3 4xy3x4y−5x
Step-by-step explanation:
there u go
The wingspan is 36 m.
Using a proportion to solve this, we write the scale factor as a ratio first: 19/38, since 19 is the size of the model's length and 38 is the real length. For the second ratio, we have 18 for the size of the model wingspan and x for the real wingspan:
19/38 = 18/x
Cross multiply:
19*x = 38*18
19x = 684
Divide both sides by 19:
19x/19 = 684/19
x = 36 m
Find the eqn. of the tangent line to the curve of f(x) = x^2 + 5x -5 at (0,-5).
Differentiate f(x) to obtain an expression for the derivative (slope of the tangent line):
f '(x) = 2x + 5
Subst. 0 for x here: f '(0) = 2(0) + 5 = 5 (at the point (0, -5))
Use the point-slope equation of a str. line to find the eqn of the tan. line:
y-k = m(x-h), where (h,k) is a point on the line and m is the slope:
y - [-5] = 5(x-0), or y+5 = 5x. Then y = 5x - 5 is the eqn. of the TL to the given curve at (0,-5).
