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lora16 [44]
3 years ago
15

Twenty percent of adults in a particular community have at least a​ bachelor's degree. Suppose x is a binomial random variable t

hat counts the number of adults with at least a​ bachelor's degree in a random sample of 100 adults from the community. If you are using a calculator with the binompdf and binomcdf​ commands, which of the following is the most efficient way to calculate the probability that more than 60 adults have a​ bachelor's degree, ​P(xgreater than​60)?
Mathematics
1 answer:
Slav-nsk [51]3 years ago
7 0

Answer:

P(X>60) = 1-binomcdf(100,0.20,60)P (X \leq 60)

Step-by-step explanation:

As we have to find an efficient way for the probability as follows:

P(X>60)

First of all we will find the remaining part of the probability that is:

P (X\leq 60 )

As the given probability is inclusive of 60 so the formula used will be:

P(X\leq 60)=binomcdf(100,0.20,60)

Now going back to the actual probability, the formula used will be:

P(X>60) = 1-binomcdf(100,0.20,60)

(Because the total probability is always 1)

I hope it will help you!

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Answer:

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Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = x\times\frac{1}{2} =\frac{x}{2} \ m.

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Now, we put the formula of area to solve:

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16=\frac{3x^2}{16}

<em>Multiplying both sides by 16 we get:</em>

<em />256=3x^2<em />

<em>Dividing both sides by 3 we get:</em>

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<em>Using square root on both sides we get:</em>

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x=\frac{16}{\sqrt{3}}

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Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.

<em>So, the base of triangle = </em>\frac{8}{\sqrt{3}} \ m.<em />

Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.

<em>Thus, the height of triangle =  </em>\frac{12}{\sqrt{3}} \ m.<em />

Therefore, the base of triangle is  \frac{8}{\sqrt{3}} \ m and the height of triangle is  \frac{12}{\sqrt{3}} \ m.

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