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Solnce55 [7]
3 years ago
14

carols bikes 1 kilometer east 4 kilometers north and then 5 kilometers east again. how far is caroll from her starting position

to the nearest tenth of a kilometer
Mathematics
2 answers:
vichka [17]3 years ago
8 0

Answer:

7.2 kilometers

Step-by-step explanation:

You are going to use the Pythagorean theorem which is a^2+b^2=c^2

so you will substitute in 6^2+4^2=c^2

36+16=x^2

52=x^2

square root 52=x

x=7.2

Volgvan3 years ago
3 0
That'd be a total of 6 km east and 4 km north.

The distance traveled from Carol's starting point, along the path described, is
1 km + 4 km + 5 km = 10 km.

However, if you want the straight line distance from starting to end point, that would be found using the Pyth. Thm.:

sqrt [ (6 km)^2 + (4 km)^2 ] = sqrt(52) = 2sqrt(13) km
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What is the absolute value of point J on the number line?
timama [110]

Answer:

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3 years ago
A bird flies from the bottom of a canyon that is 71 4/5 feet below sea level to a nest that is 875 7/10 feet above sea level. Wh
Rainbow [258]

The difference in elevation between the bottom of the canyon and the​ bird's nest is 947 1/2 feet

<h3>What is the difference in elevation between the bottom of the canyon and the​ bird's nest?</h3>

The given parameters are:

Nest = 71 4/5 feet above the seal level

Bottom of canyon = 875 7/10 below sea level

Below sea level means negative

So, we have:

Nest = 71 4/5 feet

Bottom of canyon = -875 7/10

The difference in elevation between the bottom of the canyon and the​ bird's nest is calculated as

Difference = |Nest - Bottom of canyon|

This gives

Difference = |71 4/5 - (-875 7/10)|

Evaluate the difference

Difference = |947 1/2|

Remove the absolute bracket

Difference = 947 1/2

Hence, the difference in elevation between the bottom of the canyon and the​ bird's nest is 947 1/2 feet

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1 year ago
Directions: for questions 1 through 4, find the diagonal length of each solid figure.
Alex787 [66]
\text{The length of the diagonal is }11.2\text{ mm}

Here, we want to find the diagonal of the given solid

To do this, we need the appropriate triangle

Firstly, we need the diagonal of the base

To get this, we use Pythagoras' theorem for the base

The other measures are 6 mm and 8 mm

According ro Pythagoras' ; the square of the hypotenuse equals the sum of the squares of the two other sides

Let us have the diagonal as l

Mathematically;

\begin{gathered} l^2=6^2+8^2 \\ l^2\text{ = 36 + 64} \\ l^2\text{ =100} \\ l\text{ = }\sqrt[]{100} \\ l\text{ = 10 mm} \end{gathered}

Now, to get the diagonal, we use the triangle with height 5 mm and the base being the hypotenuse we calculated above

Thus, we calculate this using the Pytthagoras' theorem as follows;

\begin{gathered} d^2=5^2+10^2 \\ d^2\text{ = 25 + 100} \\ d^2\text{ = 125} \\ d\text{ = }\sqrt[]{125} \\ d\text{ = }11.2\text{ mm} \end{gathered}

7 0
1 year ago
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