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Solnce55 [7]
3 years ago
14

carols bikes 1 kilometer east 4 kilometers north and then 5 kilometers east again. how far is caroll from her starting position

to the nearest tenth of a kilometer
Mathematics
2 answers:
vichka [17]3 years ago
8 0

Answer:

7.2 kilometers

Step-by-step explanation:

You are going to use the Pythagorean theorem which is a^2+b^2=c^2

so you will substitute in 6^2+4^2=c^2

36+16=x^2

52=x^2

square root 52=x

x=7.2

Volgvan3 years ago
3 0
That'd be a total of 6 km east and 4 km north.

The distance traveled from Carol's starting point, along the path described, is
1 km + 4 km + 5 km = 10 km.

However, if you want the straight line distance from starting to end point, that would be found using the Pyth. Thm.:

sqrt [ (6 km)^2 + (4 km)^2 ] = sqrt(52) = 2sqrt(13) km
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The distances between Jean to Joel, Jean to Marcus and Marcus to Joel form a right triangle where the distance from Marcus to Joel is the hypothenuse. We can measure the distance from Jean to Marcus and Jean to Joel by using the grid provided, since they're along the same axis. This is shown below:

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d(Marcus,Joel)² = d(Jean,Marcus)² + d(Jean,Joel)²

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