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WARRIOR [948]
3 years ago
8

Factor the polynomial expression x4 + 18x2 + 81

Mathematics
1 answer:
Akimi4 [234]3 years ago
4 0

Answer: (x^2+9)^2

Step-by-step explanation:

Rewrite it in the form a^2+2ab+b^2 , where a=x^2 and b=9.

(x^2)^2+2(x^2)(9)+9^2

Use Square of Sum: (a+b)^2= a^2+2ab+b^2

(x^2+9)^2

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Vera_Pavlovna [14]

Answer:

(Abbys slope 2/3) (Brandons slope 2/3)  Abby is correct both triangles have the same slope.

Step-by-step explanation:

3 0
2 years ago
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Karl wants to rent a bike for at most $55. He can rent a bike for $7 per hour plus a $9.50 flat fee. Any portion of an hour is c
Papessa [141]
Answer 6 hours
Reason
7x + 9.50 = 55
-9.50. -9.50 subtract from both sides
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7x = 45.50

Divide both sides by 7 to isolate x
X = 6.5
So he can rent for 6 hours (the .5 would be charged as a full hour per the problem)
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1 year ago
To cook the meat for the pasta dish takes 2 minutes less than four times the amount of time it takes to boil the noodles. The ti
bagirrra123 [75]
10 MIN i think it is :)
6 0
3 years ago
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Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find
Papessa [141]

Answer:

1) \text{P(at least one boy and one girl)}=\frac{3}{4}

2) \text{P(at least one boy and one girl)}=\frac{3}{8}

3) \text{P(at least two girls)}=\frac{1}{2}

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To  Find : The probability of each event.  

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)        

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

1) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, BGG, GBB, GBG, GGB=6

\text{P(at least one boy and one girl)}=\frac{6}{8}

\text{P(at least one boy and one girl)}=\frac{3}{4}

2) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, GBB=3

\text{P(at least one boy and one girl)}=\frac{3}{8}

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

\text{P(at least two girls)}=\frac{4}{8}

\text{P(at least two girls)}=\frac{1}{2}

4 0
3 years ago
Read 2 more answers
Please help asap!!!!
Triss [41]

Answer: B

Step-by-step explanation: The answer would be B because you would add n the number and 6 then you would multiply it by 2

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