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Kaylis [27]
3 years ago
5

Last year, a large trucking company delivered  tons of goods with an average value of $23,000 per ton. What was the total value

of the goods delivered? Write the answer in scientific notation
Mathematics
1 answer:
Kay [80]3 years ago
3 0
23x×10^3 there is your answer
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Solve for x
zhannawk [14.2K]

Answer:

x≤6 or x≥30.

but the second symbol is just less than x. I can't find the right symbol.

Step-by-step explanation:

9x+4≤58 or 1/6x-2≥3

9x≤54 or 1/6x≥5

x≤ 6 or x≥ 30

5 0
3 years ago
the length of the longer leg of a right triangle is 3 ft more than three times the length of the shorter leg. the length of the
Ulleksa [173]

with the pythagorean theorem

\begin{gathered} (4+3x)^2=x^2+(3+3x)^2 \\ 16+24x+9x^2=x^2+9+18x+9x^2 \\ 16+24x+9x^2=10x^2+18x+9 \\ 16+24x+9x^2-9=10x^2+18x+9-9 \\ 9x^2+24x+7=10x^2+18x \\ 9x^2+24x+7-18x=10x^2+18x-18x \\ 9x^2+6x+7=10x^2 \\ 9x^2+6x+7-10x^2=10x^2-10x^2 \\ -x^2+6x+7=0 \end{gathered}

using the formula of the quadratic equation

\begin{gathered} x_{1,\: 2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ x1=\frac{-6+\sqrt{6^2-4\left(-1\right)\cdot\:7}}{2\left(-1\right)}=-1 \\ x2=\frac{-6-\sqrt{6^2-4\left(-1\right)\cdot\:7}}{2\left(-1\right)}=7 \end{gathered}

the length cannot be negative, therefore x=7

length of the shorter leg is: 7ft

length of the longer leg is: 3+3(7)= 24ft

length of the hypotenuse is: 4+3(7)= 25ft

5 0
1 year ago
Six students share 8 granola bars equally. How many granola bars does each student get?
solniwko [45]

Answer:

1 whole one and a third of one.

Step-by-step explanation:

1 1/3 of a granola bar

6 0
3 years ago
Read 2 more answers
There are 3 islands A,B,C. Island B is east of island A, 8 miles away. Island C is northeast of A, 5 miles away and northwest of
Nostrana [21]

Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta (1)

Where:

AC - The distance from A to C, measured in miles.

AB - The distance from A to B, measured in miles.

BC - The distance from B to C, measured in miles.

\theta - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta

\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}

\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right) (2)

If we know that BC = 7\,mi, AB = 8\,mi, AC = 5\,mi, then the bearing from island B to island C:

\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]

\theta \approx 38.213^{\circ}

The bearing needed to navigate from island B to island C is approximately 38.213º.

8 0
3 years ago
Does anyone know how to finish this equation?
nikdorinn [45]
Not sure what you mean?
6 0
3 years ago
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