Question

Given circle O, angle A has a measure of 36° and the radius is 10 cm, find the area of sector BOC.

Answer 1

Answer:

The area of the sector BOC is A' = 31.4 $cm^{2}$

Step-by-step explanation:

Radius of the circle = 10 cm = 0.1 m

Angle of sector $\theta$ = 36°

Area of the circle A = $\pi r^{2}$

A = 3.14 × $0.1^{2}$ = 0.0314 $m^{2}$

Now area of the sector BOC is

$A' = A (\frac{\theta}{360} )$

$A' = 0.0314 (\frac{36}{360} )$

A' = 0.00314  $m^{2}$ = 31.4 $cm^{2}$

Therefore the area of the sector BOC is A' = 31.4 $cm^{2}$