Answer:
To determine the nature of roots of quadratic equations (in the form ax^2 + bx +c=0) , we need to calculate the discriminant, which is b^2 - 4 a c. When discriminant is greater than zero, the roots are unequal and real. When discriminant is equal to zero, the roots are equal and real.
Answer:
x=-0.08 and y=2.92
Step-by-step explanation:
123x + 2(x+3) = -4 y = -0.08 + 3
123x + 2x + 6 = -4 = 2.92
125x + 6 = -4
125x = -10
x= -0.08
<span><span>FV = $100*(e^rt)
FV = $100*e^(0.08*6)
FV = $100*e^0.48
FV = $100*1.616
FV = $161.6</span><span>
</span></span>
Answer: C
Step-by-step explanation:
Simplify to 4x^2 + 12x + 5 = 0 so that all the terms are on one side.
Do a part of the quadratic formula to see.
You only need to do the 
part. If it is negative, that means there are irrational solutions. If it is positive, it has two solutions. If it is 0, it has 1 solution.
It is positive so it has two solutions.
