What is the inverse of y = 2x^2 – 8?

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

6 0

$y = 2x^2 - 8 \\ 2x^2 = y + 8 \\ x^2 = \frac{y+8}{2} \\ x = \sqrt{\frac{y+8}{2}} \\ f^{-1} (x)=\sqrt{\frac{x+8}{2}}$

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