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s344n2d4d5 [400]
3 years ago
7

What is the inverse of y = 2x^2 – 8?

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
6 0
y = 2x^2 - 8 \\ 2x^2 = y + 8 \\ x^2 = \frac{y+8}{2}  \\ x = \sqrt{\frac{y+8}{2}}  \\  f^{-1} (x)=\sqrt{\frac{x+8}{2}}
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