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s344n2d4d5 [400]
3 years ago
7

What is the inverse of y = 2x^2 – 8?

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
6 0
y = 2x^2 - 8 \\ 2x^2 = y + 8 \\ x^2 = \frac{y+8}{2}  \\ x = \sqrt{\frac{y+8}{2}}  \\  f^{-1} (x)=\sqrt{\frac{x+8}{2}}
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In your computation, approximate its value as 3.14.
andrey2020 [161]

Answer: d

Step-by-step explanation:

Find the area of the rectangle.

A=l*w\\A=(15in)(12in)\\A=180in^2

Find the area of the base of the semicircle.

A=\pi r^2

12 in would be the diameter, divide by 2 to get the radius.

\frac{12}{2}=6

Plug this into the formula.

A=(3.14)(6)^2\\A=113.04in^2

Since we do not have a full circle but a semi one instead, we must divide our result by 2.

\frac{113.04}{2}=56.52in^2

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7 0
3 years ago
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GuDViN [60]

Answer:

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Step-by-step explanation:

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I hope this helps!

4 0
2 years ago
Read 2 more answers
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iVinArrow [24]

Answer:

|3x + 4 | + 6

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8 0
2 years ago
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3 years ago
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Y_Kistochka [10]
$120

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5 0
3 years ago
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