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2 years ago

What is the solution 3(2x-6)+4=8x-2(x+1)

Mathematics

1 answer:

ololo11 [35]2 years ago

6 0

Answer:

Step-by-step explanation:

3(2x-6)+4=8x-2(x+1)

We move all terms to the left:

3(2x-6)+4-(8x-2(x+1))=0

We multiply parentheses

6x-(8x-2(x+1))-18+4=0

We calculate terms in parentheses: -(8x-2(x+1)), so:

8x-2(x+1)

We multiply parentheses

8x-2x-2

We add all the numbers together, and all the variables

6x-2

Back to the equation:

-(6x-2)

We add all the numbers together, and all the variables

6x-(6x-2)-14=0

We get rid of parentheses

6x-6x+2-14=0

We add all the numbers together, and all the variables

-12!=0

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Elaine lives in Hawaii, which has a sales tax of 4%. She just bought a swimsuit whose full price was $80, but she presented the

Andrew [12]

Answer:

A : $67.60

Step-by-step explanation:

Given:

Sales tax = 4%

She just bought a swimsuit whose full price was $80,

She presented the retailer with a coupon for $15,

Question asked:

What was the total amount that Elaine paid?

Cost price of swimsuit = $80,

She presented the retailer with a coupon for = $15,

Remaining price = 80 - 15 = 65

Now, sale tax imposed = 4% of 65

= $\frac{4}{100} \times65 = \frac{ 260}{100} = 2.6$

Sale price = Remaining price after deducting coupon + sale tax

= 65 + 2.60 = 67.60

Thus , $67.60 Elaine paid to the retailer.

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3 years ago

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On a piece of paper, draw a box plot to represent the data below. Then

777dan777 [17]

Since they are already in order you know the 22 and the 61 are the upper and lower extremes. To find the median you find the number that is in the middle which is 42. To find the lower quartile find the middle number starting from the first number and the number to the left of the median (22 and 36 in this case). The loser quartile is 25. To find the upper quartile, fine the middle number between the number to the right of the median and the last number (44 and 61 in this case.) the upper quartile is 57 you then just plot it and graph it

The work is attached

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3 years ago

A soccer ball was kicked in the air and follows the path h(x)=−2x2+1x+6, where x is the time in seconds and h is the height of t

madam [21]

The ball will hit the ground at 2 seconds.

Step-by-step explanation:

Given that,

The path of the ball = h(x)=−2x2+1x+6

Here,

x is the time while h is the height of ball.

When the ball will hit the ground, the height will become zero. Therefore,

h(x)=−2x2+1x+6

0 =−2x2+1x+6

2x2 -1x - 6 = 0

This is a quadratic equation, hence by applying quadratic equation formula:

$x = \frac{-b +- \sqrt{b^{2} - 4ac } }{2a}$

here,

a = 2

b = -1

c = -6

Putting these values in formula, we get

$x = \frac{-(-1) +- \sqrt{-1^{2} - 4.2.-6 } }{2.2}$

$x = \frac{1 +- \sqrt{1 + 48 } }{4}$

$x = \frac{1 +- \sqrt{49 } }{4}$

$x = \frac{1 +- 7 }{4}$

x = 2, -3/2

As the time cannot be negative. Therefore, the ball will hit the ground at 2 seconds.

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3 years ago

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Lines m and p are perpendicular. if the slope of line m is -3 what is the slope of line p

ivann1987 [24]

For two lines to be perpendicular, their slopes must be negative reciprocals of one another, mathematically:

m1*m2=-1, in this case our reference line has a slope of -3 so:

-3m=-1 divide both sides by -3

m=-1/-3

m=1/3

So the perpendicular line will have a slope of 1/3

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3 years ago

Andrew wants to place grouping symbols in the expression

Ipatiy [6.2K]

15 + (25 – 18) ÷ 2

sorry if i'm wrong!

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3 years ago

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