Complete Question
Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.1 and the sample standard deviation was 1.2. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use α = 0.05.)
t=8.169
P-value= ?
Answer:
a) 
b) Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/ cellulose composite exceeds 48 MPa.
Step-by-step explanation:
From the question we are told that:
Sample size 
Mean 
Standard deviation 
Significance level is taken as 
t test statistics

Therefore

Critical point



Therefore
P-value from T distribution table

Conclusion

We Reject the Null Hypothesis 
Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/ cellulose composite exceeds 48 MPa.
Answer:
20,000
Step-by-step explanation:
So, the 2 is the ten thousand and the 3 is in the thousands. 4 or less means to round down so 2<u>3</u>,556 rounds down to a 0 and change the rest to a 0. 20,000. If the number 23,556 had a 5 or more in the thousands, it would have rounded to 30,000 to the nearest ten thousands but it didn't so the answer is 20,000.
Answer:

Step-by-step explanation:


The degree of f(x) is 4. Also the leading coefficient is 1 and it is positive
So as x approaches infinity then y approaches infinity
as x approaches -infinity then y approaches infinity
The first and fourth graph goes up and it satisfies the above . so we ignore the second and third graph.
Now we check the x intercepts of the first graph
x intercepts of first graph is -4 and 2
Plug in -4 for x in f(x) and check whether we get 0


Now plug in 2 for x and check

So -4 and 2 are the x intercepts that satisfies f(x)
Hence first option is the graph of 