Question

Find two consecutive odd integers such that the square of the first, added to 3 times the second is 24.

Answer 1

X^2+3(X+2)=24
X^2+3x+6-24=0
X^2+3x-18=0
(X+6)(X-3)
X+6=0. X-3=0
X=-6. X=3

. Only 3 and 5 must be a odd integer