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Novosadov [1.4K]
3 years ago
7

Find two consecutive odd integers such that the square of the first, added to 3 times the second is 24.

Mathematics
1 answer:
OLEGan [10]3 years ago
3 0
X^2+3(X+2)=24
X^2+3x+6-24=0
X^2+3x-18=0
(X+6)(X-3)
X+6=0. X-3=0
X=-6. X=3

. Only 3 and 5 must be a odd integer
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\huge \boxed{\mathbb{QUESTION} \downarrow}

  • What is the solution to the inequality -3x-42>3 ?

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

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