Tay is making jam. The recipe calls for 3 strawberries for

A paper company needs to ship paper to a large printing business. The a paper will be

eimsori [14]

Given :

A paper company needs to ship paper to a large printing business.

The paper will be shipped in small boxes and large boxes.

Each small box of paper weighs 50 pounds and each large box of paper weighs 80 pounds. A total of 19 boxes of paper were shipped weighing 1280 pounds altogether.

Find :

Determine the number of small boxes shipped and the number of large boxes shipped.

Calculations :

Let "S" be small boxes and "L" be large boxes.

Small box + Large box = 19

50S + 80L = 1280

→ 5S + 8L = 128

→ 5 (19 - L) + 8L = 128

→ 3L = 128 - 95

→ L = 33/3

→ L = 11ㅤㅤ

Finding the small box:

→ S = 19 - L

→ S = 19 - 11

→ S = 8

Therefore ,

Large boxes = 11.

Small boxes = 8.

orrrrrr

The number of small boxes is 8 and that of the large boxes is 11.

Step-by-step explanation:

Each small box of paper weighs 50 pounds and each large box of paper

weighs 80 pounds. A total of 19 boxes of paper were shipped weighing 1280 pounds altogether.

Let there are x small boxes and y large boxes.

Then,

x + y = 19 ............ (1) and

50x + 80y = 1280

⇒ 5x + 8y = 128 ............... (2)

Now, solving equations (1) and (2) we get,

5( 19 - y) + 8y = 128

⇒ 3y = 128 - 95 = 33

⇒ y = 11

Now, from equation (1) we get, x = 19 - y = 19 - 11 = 8

Therefore, the number of small boxes is 8 and that of the large boxes is 11. (Answer)

8 0

3 years ago

15 is what percent of 40? Pls Show Work Thx

Free_Kalibri [48]

15 = rate * 40
rate = 15/40
rate = 0.375 * 100% = 37.5%

4 0

4 years ago

Read 2 more answers

3(c+4) what's da answer

lisov135 [29]

Answer:

3c + 12

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Be prepared to explain the steps you would take to solve a real-world problem

shusha [124]

Answer:

Be prepared as the questions states. Good luck.

Step-by-step explanation:

7 0

3 years ago

PLEASE HELP AND SHOW WORK!!

Nastasia [14]

Answer:

Pipe 1 alone fills a tank in 10 min

Pipe 2 alone fills the tank in 20 min

If both are turned on together, how long will it take to fill the tank???

Pipe 1 fills at the RATE of 1/10th tank per min

Pipe 2 fills at the RATE of 1/20th tank per min

Pipe 1 + Pipe 2 fills at the rate of 1/10+1/20 or 3/20th tank per min

Let x= time to fill the tank

(3/20)(x)=1 Where 1 denotes a full tank (Multiply both sides by 20)

3x=20

x=6 2/3 min----------both working together

NOW YOUR PROBLEM

Let x= amount of time for smaller pipe to fill the tank

Then (x-5)=amount of time for larger pipe to fill the tank

NOW HERE'S WHERE THE RECIPROCAL COMES IN:

The smaller pipe fills the tank at the RATE of 1/x cu units per min

The larger tank fills the tank at the RATE of 1/(x-5) cu units per min

Together, they fill the tank at the rate of 1/x+(1/(x-5)) cu units per min

But now we are told that together the fill the tank in 11 1/9 minutes. so our equation to solve is:

(1/x+(1/(x-5))(11 1/9)=1 where 1 denotes a full tank. In fact, in each of the above reciprocals, the 1 denotes a full tank.

So, dividing both sides by 11 1/9, we get:

1/x+(1/(x-5)=1/(11 1/9)-------------- which is your equation

I assume that you have no problems solviing this eq.

Hope this helps----ptaylor

Step-by-step explanation:

7 0

3 years ago