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mamaluj [8]
3 years ago
13

When factoring a trinomial of the form ax2 + bx + c where a and b are both positive and c is negative, you need to find two numb

ers, m and n, such that ax2 + bx + c = ax2 + mx + nx + c and _________.
A.
m and n are both positive
B.
m and n are both negative
C.
m is positive, n is negative, and |m|>|n|
D.
m is positive, n is negative, and |n|>|m|
Mathematics
2 answers:
vaieri [72.5K]3 years ago
4 0
M * n = a * c
Since a and b are positive and c is negative.
So, a * c is negative which means that m * n is negative, i.e. m is positive, n is negative.

Also m + n = b and since b is positive, then |m| > |n|.

Therefore, option C is the correct answer.
Scilla [17]3 years ago
3 0

Answer:

Step-by-step explanation:

Wrong. I just took the test and it's D.

Here's why:

when ax2-[mx+nx]-c

m and n need to have a positive and a negative coefficient.

if m is positive and a n is negative then n needs to be greater than m so the solution will also be negative to satisfy the need for [mx+nx] to be negative.

;)

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