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Blizzard [7]
3 years ago
15

A triangle has a height that is 4 /3 the length of its base. If the length of its base is 24 cm, what is its area?

Mathematics
2 answers:
ASHA 777 [7]3 years ago
6 0
Triangle Area = ½ * height * base

base = 24 therefore
height = (4/3) * base = (4/3) * base = 32 cm

Triangle Area = ½ * 32 * 24
= 384 cubic centimeters


elena55 [62]3 years ago
5 0

Answer:

384

Step-by-step explanation:

on usatestprep it is b

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Answer:

g(x)

Step-by-step explanation:

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Folding a rectangle along one diagonal results in a shape whose area is 2/3 that of the original
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Answer:

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Step-by-step explanation:

<em>Refer to attached picture</em>

Given rectangle ABCD. Its folded shape is given as well.

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We need to find the value of angle AOC or BOD.

This is going to be 2α, which is easy to find out. BOD is cut by the angle bisector, each of the angles is α.

Let the area of the rectangle is A, then the folded shape has area 2/3A.

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<u>From the triangle CBD we get:</u>

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<u>Then</u>

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Now, lets find the area of the folded shape.

It is the area of the rectangle minus the area of the triangle CMB as this part  is lost as part of overlap.

<u>Area of the triangle:</u>

  • A = 1/2dh

<u>Since h/(d/2) = tan α ⇒ h = 1/2d tan α, the area is:</u>

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<u>The acute angle formed by the two diagonals of the rectangle is:</u>

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2 years ago
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Step-by-step explanation:

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Step-by-step explanation:

\displaystyle\\

\left \{ {{x^2y=16\ \ \ \ \ (1)} \atop {x^2+4y+16=0\ \ \ \ \ (2)}} \right. .\\

Multiply\  both\  sides\  of\  the\  equation\ (2)\   by\  y\  (y\neq 0):\\

x^2y+4y^2+16y=0\\

We\  substitute\  equation\  (1)\  into\  equation\  (2):\\

16+4y^2+16y=0\\

4y^2+16y+16=0\\

4*(y^2+4y+4)=0\\

4*(y^2+2*y*2+2^2)=0\\

4*(y+2)^2=0\\

Divide\  both\  sides\  of\  the \ equation\  by\  4:\\

(y+2)^2=0\\

(y+2)*(y+2)=0\\

So,\ y+2=0\\

y=-2.\\

\displaystyle\\We\  substitute\  the\  value\  of\  y\  into\  equation\  (1):\\x^2*(-2)=16\\Divide\  both\  sides\  of\  the \ equation\  by\  -2:\\x^2=-8\\x^2\geq 0\\ Hence,\ the\ system\ has\ no\ solution.

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