Answer:
1) ![Range = Max-Min= 5.2-0.8=4.4](https://tex.z-dn.net/?f=%20Range%20%3D%20Max-Min%3D%205.2-0.8%3D4.4)
The sample variance can be calculated with this formula:
![s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}](https://tex.z-dn.net/?f=%20s%5E2%20%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20%28X_i%20-%5Cbar%20X%29%5E2%7D%7Bn-1%7D)
And we got:
![s^2 = 3.324](https://tex.z-dn.net/?f=%20s%5E2%20%3D%203.324)
And the sample deviation would be:
![s= \sqrt{3.324}= 1.823](https://tex.z-dn.net/?f=%20s%3D%20%5Csqrt%7B3.324%7D%3D%201.823)
2) ![\bar X =\frac{\sum_{i=1}^n X_i}{n}](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%3D%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20X_i%7D%7Bn%7D)
And we got:
![\bar X= 3.12](https://tex.z-dn.net/?f=%20%5Cbar%20X%3D%203.12)
The median since we have 10 values would be the average between the 5th and 6th observations from the dataset ordered and we got:
![Median= \frac{2.2+3.6}{2}= 2.9](https://tex.z-dn.net/?f=%20Median%3D%20%5Cfrac%7B2.2%2B3.6%7D%7B2%7D%3D%202.9)
And finally the mode would be the most repated value and we got:
![Mode= 5.2](https://tex.z-dn.net/?f=%20Mode%3D%205.2)
3) ![Median](https://tex.z-dn.net/?f=%20Median%3CMean%3CMode)
So then we can conclude that probably this distirbution is left skewed
Step-by-step explanation:
We have the following dataset given:
1.1, 5.2, 3.6, 5.0, 4.8, 1.8, 2.2, 5.2, 1.5, 0.8
Part 1
We can order the dataset on increasing way and we got:
0.8 1.1 1.5 1.8 2.2 3.6 4.8 5.0 5.2 5.2
The range can be calculated like this:
![Range = Max-Min= 5.2-0.8=4.4](https://tex.z-dn.net/?f=%20Range%20%3D%20Max-Min%3D%205.2-0.8%3D4.4)
The sample variance can be calculated with this formula:
![s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}](https://tex.z-dn.net/?f=%20s%5E2%20%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20%28X_i%20-%5Cbar%20X%29%5E2%7D%7Bn-1%7D)
And we got:
![s^2 = 3.324](https://tex.z-dn.net/?f=%20s%5E2%20%3D%203.324)
And the sample deviation would be:
![s= \sqrt{3.324}= 1.823](https://tex.z-dn.net/?f=%20s%3D%20%5Csqrt%7B3.324%7D%3D%201.823)
Part 2
The mean can be calculated with this formula:
![\bar X =\frac{\sum_{i=1}^n X_i}{n}](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%3D%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20X_i%7D%7Bn%7D)
And we got:
![\bar X= 3.12](https://tex.z-dn.net/?f=%20%5Cbar%20X%3D%203.12)
The median since we have 10 values would be the average between the 5th and 6th observations from the dataset ordered and we got:
![Median= \frac{2.2+3.6}{2}= 2.9](https://tex.z-dn.net/?f=%20Median%3D%20%5Cfrac%7B2.2%2B3.6%7D%7B2%7D%3D%202.9)
And finally the mode would be the most repated value and we got:
![Mode= 5.2](https://tex.z-dn.net/?f=%20Mode%3D%205.2)
Part 3
For this case we know that:
![Median](https://tex.z-dn.net/?f=%20Median%3CMean%3CMode)
So then we can conclude that probably this distirbution is left skewed