Answer:
16 i think
Step-by-step explanation:
Answer:
6 3 /11
Step-by-step explanation:
10 5/11 - 4 2/11
since they already have a common denominator
10 5/ 11
- 4 2 /11
-------------
6 3 /11
Consider such events:
A - slip with number 3 is chosen;
B - the sum of numbers is 4.
You have to count
Use formula for conditional probability:
1. The event consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event is
2. The event consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event is
3. Then
Answer:
To solve for P(QIR) we use the formula:
P(QIR)=[P(Q∩R)]/P(R)
But from the diagram:
P(Q∩R)=3/22
P(R)=7/22
hence
P(QIR)=3/22÷7/22=3/7
The answer is B if you solve for x